<span>This is a quadratic equation . We order to equate to zero
</span>2x²<span> – 7 = 9
</span>
2x² - 7-9 = 0
2x² - 16 = 0
This equation is a binomial
2* (x² - 8) = 0
<span>We choose the simplest method . The equation with practice it can be calculated in the memory
</span><span>
The product is equal to 0 if one of the factors is zero
</span>
2≠0 ∨ x² - 8 = 0
x² = √8
x = √8 ∨ x= - √8
Answer : x = √8 ∨ x = -√8
Answer:
ffyftxrrxrrxcvcmuvcyztzxvujgyh
Step-by-step explanation:
✋☝☝✊✋❤❤❤
Answer:
The answer to the question are
(B) The set is not a vector space because it is not closed under addition. and
(D) The set is not a vector space because an additive inverse does not exist.
Step-by-step explanation:
To be able to identify the possible things that can affect a possible vector space one would have to practice on several exercises.
The vector space axioms that failed are as follows
(B) The set is not a vector space because it is not closed under addition.
(2·x⁸ + 3·x) + (-2·x⁸ +x) = 4·x which is not an eighth degree polynomial
(D) The set is not a vector space because an additive inverse does not exist.
There is no eight degree polynomial = 0
The axioms for real vector space are
- Addition: Possibility of forming the sum x+y which is in X from elements x and y which are also in X
- Inverse: Possibility of forming an inverse -x which is in X from an element x which is in X
- Scalar multiplication: The possibility of forming multiplication between an element x in X and a real number c of which the product cx is also an element of X
Answer:
104.4 for A.
Step-by-step explanation:
