The answer is -4 final answer
Answer:
<u>The system has two solutions:</u>
<u>x₁ = 5 ⇒ y₁ = -10</u>
<u>x₂ = -2 ⇒ y₂ = 11</u>
Step-by-step explanation:
Let's solve the system of equations, this way:
y = -3x + 5
y = x ² - 6x - 5
Replacing y in the 2nd equation:
y = x ² - 6x - 5
-3x + 5 = x ² - 6x - 5
x ² - 3x - 10 = 0
Solving for x, using the quadratic formula:
(3 +/- √(9 -4 * 1 * -10))/2 * 1
(3 +/- √9 + 40)/2
(3 +/- √49)/2
(3 +/- 7)/2
x₁ = 10/2 = 5
x₂ = -4/2 = -2
x₁ = 5 ⇒ y₁ = -10
x₂ = -2 ⇒ y₂ = 11
<u>As we can see the system has two different solutions</u>
Answer:
(x,y)=(-13,-12)
Step-by-step explanation:
5x - 7y = 19
7x - 7y = -7 Multiply both sides of the equation by -1
Which then gives you :
5x-7y=19 Sum the equations vertically to eliminate
-7x+7y=7 at least on variable
-2x=26 Divide both sides of the equation by -2
X=-13 Substitute the given value of x into the equation 7x - 7y =-7
7 x(-13)-7y=-7 solve the equation for y
y=-12
Thus gives you (-13,-12)
Hope this was useful!!! Sorry if it's wrong.
Answer:
x = 13
x = -5
Step-by-step explanation:
