The table below shows the number of e-mails received each day by a

Find the percent of increase from 40 gallons to 89 gallons. Round to the nearest tenth of a percent if necessary.

fredd [130]

Solution

- 89 gallons contains 40 gallons twice such that:

$89=40+40+9$

- This means that we can find at least 200% of 40 gallons in 89 gallons. This gives us what to expect.

- To get the percentage we are looking for, we should use the formula:

$\frac{\text{new}}{\text{old}}\times100\text{ \%}$

New, in this case, is 89 gallons, Old is 40 gallons.

- Thus, we can calculate the percentage as follows:

$\begin{gathered} \frac{89}{40}\times100 \\ =2.225\times100 \\ =222.5\text{ \%} \end{gathered}$

Thus, the answer is 222.5%

8 0

1 year ago

If f(x)=3x+5 and q(x)=0, show that f(x)+q(x)=f(x).

alex41 [277]

Step-by-step explanation:

f(x)=3x+5
q(x)=0

f(x)+q(x)

➜3x+5+0

➜3x+5

➜f(x)

<h3>Hence proved</h3>

8 0

3 years ago

493 is 32% of what number ?

Mashcka [7]

493÷x=32÷100
x=1540.625

3 0

3 years ago

Read 2 more answers

For the first part of the obstacle course, Helena needs to sprint as fast as she can to Checkpoint A, which is 5 units north of

andrew11 [14]

Answer:

If the four number sentences at the bottom are the choices for your answer the correct one would be choice A or 1.

I hope this is what you meant if not I'll try to take my answer down and try to answer it again correctly!

5 0

2 years ago

Dustin has a bag of marbles with 4 blue marbles, 4 white marbles, and 3 red marbles.

diamong [38]

Answer:

A.

$\dfrac{6}{55}$

B.

$\dfrac{6}{55}$

C.

$\dfrac{4}{165}$

Step-by-step explanation:

Dustin has a bag of marbles with 4 blue marbles, 4 white marbles, and 3 red marbles. There are 11 marbles in total.

A. The probability that the first marble drawn is blue marble is

$\dfrac{4}{11},$

the probability that the second marble drawn is red marble is

$\dfrac{3}{10}$

The probability that the first marble drawn is blue and the second is red is

$\dfrac{4}{11}\cdot \dfrac{3}{10}=\dfrac{12}{110}=\dfrac{6}{55}$

B. The probability that the first marble drawn is red marble is

$\dfrac{3}{11},$

the probability that the second marble drawn is white marble is

$\dfrac{4}{10}$

The probability that the first marble drawn is red and the second is white is

$\dfrac{3}{11}\cdot \dfrac{4}{10}=\dfrac{12}{110}=\dfrac{6}{55}$

C. The probability that the first marble drawn is blue marble is

$\dfrac{4}{11},$

the probability that the second marble drawn is blue marble is

$\dfrac{3}{10},$

the probability that the third marble drawn is blue marble is

$\dfrac{2}{9},$

The probability that the first, second and third marbles drawn are blue is

$\dfrac{4}{11}\cdot \dfrac{3}{10}\cdot \dfrac{2}{9}=\dfrac{24}{990}=\dfrac{4}{165}$

8 0

3 years ago