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3 years ago

14

Parallelogram JSTP∼parallelogram BFMY

1 answer:

Serhud [2]3 years ago

8 0

Answer:

$\angle P=\angle Y;$

$\overline {ST}$ and $\overline {FM};$

$\angle T=\angle M;$

$\overline {JP}$ and $\overline {BY}.$

Step-by-step explanation:

Similar figures have proportional corresponding sides and congruent corresponding angles. If parallelogram JSTP is similar to parallelogram BFMY, then

$\angle J=\angle B;$
$\angle S=\angle F;$
$\angle T=\angle M;$
$\angle P=\angle Y;$
$\dfrac{JS}{BF}=\dfrac{ST}{FM}=\dfrac{TP}{MY}=\dfrac{JT}{BM}=\dfrac{JP}{BY}=\dfrac{SP}{FY}.$

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