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3 years ago

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Helpme quickly worth 10 pts... On Thursday, a website received x advertisement orders. On Friday, the website received 8 more ad

vertisement orders than on Thursday.
Which expression represents the total number of advertisement orders received over these two days?

A. 2x+8

B. x+8

C. 2(x+8)

D. 8x

1 answer:

Sever21 [200]3 years ago

3 0

I am thinking B, because if you think about it you would write it as x+ 8 because he first got x and then he added 8 more to that x and then they tell you how much they recived in those days if you multiply the like in answer D you will get to much and their askign for the total of teh 2 days so you would add them,... Hope this helped

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Margot has 21 1/2 pounds of flour 8 pounds of butter and 18 1/2 ponds of sugar to make shortbread cookies if she makes 12 batche

adell [148]

Answer:

<em>4 pounds of ingredients are used in each batch.</em>

Step-by-step explanation:

Amount of flour = $21\frac{1}{2}pounds = \frac{43}{2}pounds$

Amount of butter = 8 pounds

Amount of sugar = $18\frac{1}{2}pounds= \frac{37}{2} pounds$

So, the <u>total amount of all ingredients</u> will be: $(\frac{43}{2}+\frac{37}{2}+8)pounds = (\frac{43+37+16}{2}) pounds= \frac{96}{2} pounds = 48 pounds$

Given that, she makes 12 batches of cookies using all the ingredients.

Thus, the amount of ingredients used in each batch $=\frac{48}{12} pounds = 4 pounds$

5 0

3 years ago

Please help me algebra 2 question

iren [92.7K]

Set the two equal to each other and solve for x

-2x+1 = -2x²+1
-2x= -2x²
x=x²
x²-x=0
x(x-1) =0, so x is either 0 or 1

two solutions, namely (0,1) and (1,1)

5 0

3 years ago

Assume the hold time of callers to a cable company is normally distributed with a mean of 5.5 minutes and a standard deviation o

Ierofanga [76]

Answer:

The percent of callers are 37.21 who are on hold.

Step-by-step explanation:

Given:

A normally distributed data.

Mean of the data, $\mu$ = 5.5 mins

Standard deviation, $\sigma$ = 0.4 mins

We have to find the callers percentage who are on hold between 5.4 and 5.8 mins.

Lets find z-score on each raw score.

⇒ $z_1=\frac{x_1-\mu}{\sigma}$ ...raw score, $x_1$ = $5.4$

⇒ Plugging the values.

⇒ $z_1=\frac{5.4-5.5}{0.4}$

⇒ $z_1=-0.25$

For raw score 5.5 the z score is.

⇒ $z_2=\frac{5.8-5.5}{0.4}$

⇒ $z_2=0.75$

Now we have to look upon the values from Z score table and arrange them in probability terms then convert it into percentages.

We have to work with P(5.4<z<5.8).

⇒ $P(5.4$

⇒ $P(-0.25$

⇒ $P(z$

⇒ $z(1.5)=0.7734$ and $z(-0.25)=0.4013$ .<em>..from z -score table.</em>

⇒ $0.7734-0.4013$

⇒ $0.3721$

To find the percentage we have to multiply with 100.

⇒ $0.3721\times 100$

⇒ $37.21$ %

The percent of callers who are on hold between 5.4 minutes to 5.8 minutes is 37.21

4 0

3 years ago

3x +15=75 what is the value of x

kifflom [539]

Answer:

X=20

you subtract 15 from 75 to get 60 then divide 60 by 3 to get 20

3 0

3 years ago

Read 2 more answers

The given curve is rotated about the y-axis. find the area of the resulting surface. y = 1 3 x3/2, 5 ≤ x ≤ 12

Katyanochek1 [597]

The area of the resulting figure will be given by:
∫f(x)dx
f(x)=13/2x^3
thus
∫f(x)dx=13/2∫x³dx=13/8[x^4]
integrating over the inerval
13/8(12^4)-13/8(5^4)
=32680+3/8 sq. units
=

7 0

3 years ago