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3 years ago

10q - 12q + -7q =15

Mathematics

1 answer:

Crank3 years ago

4 0

Answer:

=1 2/3

Step-by-step explanation:

Remove parentheses so it’s 10q-12q-7q=15

Collect the terms so it’s -9q=15 then divide both sides by -9

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x = 8

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Compare the weather on two different days using an inequality. Then see if their comparisons change by finding the absolute valu

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Inequalities are used to compare unequal expressions.

The actual comparison is: $\mathbf{-3.5 < 5}$ or $\mathbf{5 > -3.5}$

The temperatures are given as:

$\mathbf{Temperature = -3.5F,\ \ 5F,\ \ 1.5F,\ \ -0.5F,\ \ -2F,\ \ 2.5F,\ \ -4F}$

From the above list, we have:

$\mathbf{Day \ 1= -3.5F}$

$\mathbf{Day \ 2= 5F}$

By comparison,

$\mathbf{-3.5 < 5}$ or $\mathbf{5 > -3.5}$

Using absolute values, the inequalities are:

$\mathbf{|-3.5| < |5|}$ or $\mathbf{|5| > |-3.5|}$

Hence, the actual comparison is:

$\mathbf{-3.5 < 5}$ or $\mathbf{5 > -3.5}$

Read more about inequalities and absolute values at:

brainly.com/question/24797699

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3 years ago

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A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions

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Dimensions are length 20 meter and width 14 meter

Solution:

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

A rectangle has width that is 6 meters less than the length

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

The area of the rectangle is given by formula:

$Area = length \times width$

Substituting the values we get,

$Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0$

Solve the above equation by quadratic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}$

$a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14$

Since, length cannot be negative, ignore a = -14

Thus solution of length is a = 20

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

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3 years ago