The answer is -76.1 meters.
The submarine elevation before rising is -203 meters (it is negative because it is under the sea level which has 0 elevation): d₁ = -203 m
After the first rising, it moved 64.5 m: l₁ = 4.3 · 15 = 64.5 m
After the second rising, it moved 62.4 m: l₂ = 5.2 · 12 = 62.4 m
So, to calculate the elevation of the submarine after rising (d₂), we will add (because it is not going deeper, it rises toward the elevation of 0) two movements to the elevation before rising:
d₂ = d₁ - (l₁ + l₂) = -203 + (64.5 + 62.4) = -203 + 126.9 = -203 + 126.9 = -76.1.
Answer:
b. 4.1 shirts
Step-by-step explanation:
Given data:
number of terms = 12
Terms given are 3, 4, 8, 5, 2, 5, 0, 5, 3, 4, 3, 7
Mean = (sum of terms)/ (number of terms)
Mean = (3 +4+ 8+ 5+2+5+0+ 5+ 3+ 4+3+ 7)/12
Mean = 49/12
Mean = 4.083
Mean = 4.1 (<em>to the nearest tenth)</em>
<h3>f(x)=3x³-13x²-3x+45</h3><h3>f(x)=3x³-9x²-4x²+12x-15x+45</h3><h3>f(x)=3x²(x-3)-4x(x-3)-15(x-3)</h3><h3>f(x)=(x-3)(3x²-4x-15)</h3><h3>f(x)=(x-3)(x-3)(3x+5)</h3><h2>f(x)=(x-3)²(3x+5)</h2>
<h3><u>Roots:</u></h3><h3>x=3</h3><h3>x=-5/3</h3>
This will come out to 35.1
Hope this helps ya!
