X^2 + y^2 - 2x + 8y - 47 = 0
x^2 + y^2 - 2x + 8y = 47
(x^2 - 2x) + (y^2 + 8y) = 47
(x^2 - 2(1)x) + (y^2 + 2(4)y) = 47
(x^2 - 2(1)x + 1^2) + (y^2 + 2(4)y + 4^2) = 47 + 1^2 + 4^2
(x - 1)^2 + (y + 4)^2 = 64 = 8^2
r=8
Answer:
See attached picture.
Step-by-step explanation:
h(x) has two functions in it. It has y = x and y =-x. Both have a slope of 1 or -1 and are diagonal lines. This means only 2 graphs of the four choices are possible answers.
Notice that y = -x has an interval that is greater than or equal to. This means it is marked with a closed or filled in dot at its start. This means choice B is the correct choice.
The probability that the hypothesis test will result in a type ii error, β is 0.20.
In this question,
A type II error is one of two types of statistical errors that can result from a hypothesis test (the other being a type I error). A type II error will occur if the statistical test is not powerful enough. And it occurs when one rejects the alternative hypothesis (fails to reject the null hypothesis) when the alternative hypothesis is true.
The probability of a type II error is denoted by *beta*, β.
Power of a test = 0.80
The relation between power of a test and type II error is given as,
Power = 1 - type II error
⇒ Type II error, β = 1 - 0.80
⇒ Type II error, β = 0.20
Hence we can conclude that the probability that the hypothesis test will result in a type ii error, β is 0.20.
Learn more about type II error here
brainly.com/question/14392957
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Answer:
The answer is -17
Step-by-step explanation:
All you have to do is multpily 5 and -4 then add 3
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