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Andrej [43]
4 years ago
10

The cost of tuition at Cornell University is 43,000 per year when rounded to the nearest thousand what is the greatest possible

amount the tuition could be? what is the least possible amount the tuition could be? explain your thinking.
Mathematics
1 answer:
melomori [17]4 years ago
3 0
The cost of the tuitions will if you round off 43:000 it would $43
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The first answer is correct thanks for points
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7 is right bit I just don't know on 5 and on how to interpret its meaning so 5 is 0.90 and 6 12 just help me explain the meaning
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Step-by-step explanation:

did you play free fire

7 0
3 years ago
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Identify the equation of a line in slope- intercept form that is perpendicular to y = -1/3 x + 2 and passes through (2, 1) Show
Dmitriy789 [7]

Answer: y = 3x - 5

Step-by-step explanation:

The equation of a straight line can be represented in the slope intercept form as

y = mx + c

Where

c = intercept

m = slope = (change in the value of y in the y axis) / (change in the value of x in the x axis)

The equation of the given line is

y = -1/3x + 2

Comparing with the slope intercept form, slope = - 1/3

If two lines are perpendicular, it means that the slope of one line is the negative reciprocal of the slope of the other line. Therefore, the slope of the line passing through

(2, 1) is 3/1 = 3

To determine the intercept, we would substitute m = 3, x = 2 and y = 1 into y = mx + c. It becomes

1 = 3 × 2 + c = 6 + c

c = 1 - 6 = - 5

The equation becomes

y = 3x - 5

8 0
3 years ago
What is the volume of the box
Maurinko [17]

Answer: L•W•H

Step-by-step explanation:

L=length W=width H=height •= times(multiply)

5 0
2 years ago
Simplify the expression 5^3 x 5^-5
kotykmax [81]

Answer:

\frac{1}{5^2} --- 1 over 5 squared

Step-by-step explanation:

When multiplying terms with a common base, you just add the exponents:

x^a\times x^b=x^{a+ b}

That's true even when you don't have any exponents.

5\times5=5^1\times5^1=5^{1+1}=5^2=25

\rightarrow5^3\times5^{-5}\\\rightarrow5^{3-5}\\\rightarrow5^{-2}

A negative exponent isn't fully simplified, so there's another rule to use:

x^{-y}=\frac{1}{x^y}

That is '1 over x to the y' if it's too small to read.

\rightarrow5^{-2}=\frac{1}{5^2}

4 0
3 years ago
Read 2 more answers
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