Ask question

Ask question

All categories

SCORPION-xisa [38]

4 years ago

11

g Recall the method used to obtain a confidence interval for the difference between two population means for matched samples. (a

) The following data are from matched samples taken from two populations. Compute the difference value for each element. (Use Population 1 − Population 2.) Element Population Difference 1 2 1 11 8 2 7 8 3 9 6 4 12 7 5 13 10 6 15 15 7 15 14

1 answer:

Dovator [93]4 years ago

8 0

Answer:

Step-by-step explanation:

Population 1: 11, 7, 9, 12, 13, 15, 15

Population 2: 6, 6, 4, 5, 8, 13, 12

Mean = sum of terms/number of terms

For population 1,

number of terms = 7

Mean = (11 + 7 + 9 + 12 + 13 + 15 + 15)/7 = 82/7 = 11.7

For population 2,

Number of terms = 7

Mean = (6 + 6 + 4 + 5 + 8 + 13 + 12)/7 = 7.71

The difference value for each element is

(11 + 7 + 9 + 12 + 13 + 15 + 15) - (6 + 6 + 4 + 5 + 8 + 13 + 12) = (5, 1, 5, 7, 5, 2, 3)

The difference between the two means is

Mean of population 1 - mean of population 2

Difference = 11.7 - 7.71 = 3.99

You might be interested in

On an alien planet with no atmosphere, acceleration due to gravity is given by g = 12m/s^2. A cannonball is launched from the or

almond37 [142]

Answer:

a) $\vec r (t) = \left[(90\cdot \cos \theta)\cdot t \right]\cdot i + \left[(90\cdot \sin \theta)\cdot t -6\cdot t^{2} \right]\cdot j$ , b) $\theta = \frac{\pi}{4}$ , c) $y_{max} = 84.375\,m$ , $t = 3.75\,s$ .

Step-by-step explanation:

a) The function in terms of time and the inital angle measured from the horizontal is:

$\vec r (t) = [(v_{o}\cdot \cos \theta)\cdot t]\cdot i + \left[(v_{o}\cdot \sin \theta)\cdot t -\frac{1}{2}\cdot g \cdot t^{2} \right]\cdot j$

The particular expression for the cannonball is:

$\vec r (t) = \left[(90\cdot \cos \theta)\cdot t \right]\cdot i + \left[(90\cdot \sin \theta)\cdot t -6\cdot t^{2} \right]\cdot j$

b) The components of the position of the cannonball before hitting the ground is:

$x = (90\cdot \cos \theta)\cdot t$

$0 = 90\cdot \sin \theta - 6\cdot t$

After a quick substitution and some algebraic and trigonometric handling, the following expression is found:

$0 = 90\cdot \sin \theta - 6\cdot \left(\frac{x}{90\cdot \cos \theta} \right)$

$0 = 8100\cdot \sin \theta \cdot \cos \theta - 6\cdot x$

$0 = 4050\cdot \sin 2\theta - 6\cdot x$

$6\cdot x = 4050\cdot \sin 2\theta$

$x = 675\cdot \sin 2\theta$

The angle for a maximum horizontal distance is determined by deriving the function, equalizing the resulting formula to zero and finding the angle:

$\frac{dx}{d\theta} = 1350\cdot \cos 2\theta$

$1350\cdot \cos 2\theta = 0$

$\cos 2\theta = 0$

$2\theta = \frac{\pi}{2}$

$\theta = \frac{\pi}{4}$

Now, it is required to demonstrate that critical point leads to a maximum. The second derivative is:

$\frac{d^{2}x}{d\theta^{2}} = -2700\cdot \sin 2\theta$

$\frac{d^{2}x}{d\theta^{2}} = -2700$

Which demonstrates the existence of the maximum associated with the critical point found before.

c) The equation for the vertical component of position is:

$y = 45\cdot t - 6\cdot t^{2}$

The maximum height can be found by deriving the previous expression, which is equalized to zero and critical values are found afterwards:

$\frac{dy}{dt} = 45 - 12\cdot t$

$45-12\cdot t = 0$

$t = \frac{45}{12}$

$t = 3.75\,s$

Now, the second derivative is used to check if such solution leads to a maximum:

$\frac{d^{2}y}{dt^{2}} = -12$

Which demonstrates the assumption.

The maximum height reached by the cannonball is:

$y_{max} = 45\cdot (3.75\,s)-6\cdot (3.75\,s)^{2}$

$y_{max} = 84.375\,m$

7 0

3 years ago

Describe the differences and<br> similarities between the following<br> y = 2x – 3 and y < 2x – 3

mina [271]

Answer:

Y = -2x and Y = |-2x| correct me

8 0

3 years ago

Given f(x) = 3x^3+ kx – 11, and x – 1 is a factor of f(x), then what is the value<br> of k?

STatiana [176]

let's recall the remainder theorem.

we know that (x-1) is a factor, that means x -1 = 0 or x = 1.

since we know that (x-1) is a factor, then dividing the polynomial by it will give us a remainder of 0, which correlates with saying that f(1) = 0, in this case, so we can simply plug in "1" as the argument, knowing it gives 0.

$f(x)=3x^3+kx-11\\\\[-0.35em]~\dotfill\\\\\stackrel{0}{f(1)}=3(1)^3+k(1)-11\implies \stackrel{f(1)}{0}=3+k-11\implies 0=-8+k\implies 8=k$

7 0

2 years ago

What is the answer for -8n=13

KatRina [158]

Answer:

-13/8

Step-by-step explanation:

u divied by -8 to get n by itself

4 0

3 years ago

Read 2 more answers

Which expression is equivalent to |a|≤5 ?

sladkih [1.3K]

Answer:

I think its the first one but not 100 % sure

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers