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3 years ago

Solve by completing the square b^2 + 6b - 16 = 0

1 answer:

3 0

         b² + 6b - 16 = 0
      b² + 8b - 2b - 16 = 0
b(b) + b(8) - 2(b) - 2(8) = 0
   b(b + 8) - 2(b + 8) = 0
      (b - 2)(b + 8) = 0
b - 2 = 0 or    b + 8 = 0
<u>   + 2 + 2</u> <u> - 8 - 8</u>
   b = 2 b = -8

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Answer:

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Step-by-step explanation:

we know that

The area of a regular hexagon can be divided into 6 equilateral triangles

step 1

Find the area of one equilateral triangle

$A=\frac{1}{2}(b)(h)$

we have

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substitute

$A=\frac{1}{2}(8)(4\sqrt{3})$

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step 2

Find the area of 6 equilateral triangles

$A=(6)16\sqrt{3}=96\sqrt{3}=166.3\ units^{2}$

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