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Arte-miy333 [17]
3 years ago
15

Is 7.2 bigger than 7.21

Mathematics
2 answers:
Zepler [3.9K]3 years ago
6 0

Answer:

yes 7.2 is bigger than 7.21

Step-by-step explanation:

.2 is 2/10 and .21 is 21/100 which is much smaller that .2

Paraphin [41]3 years ago
4 0

Answer:

yes

Step-by-step explanation:

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Sue buys 5 pieces of fabric.Each piece is 1 7/10 yards long.What is the total length of the fabric she buys?One yard of the fabr
irina [24]

Answer:

The total length of fabric sue buys is 8.5 yards and total cost of the fabric is $42.5 .

Step-by-step explanation:

As given

Sue buys 5 pieces of fabric.

Each\ piece\ is\ 1 \frac{7}{10}\ yards\ long.

i.e

Each\ piece\ is\ \frac{17}{10}\ yards\ long.

Total\ length\ of\ fabric\ sue\ buys = \frac{5\times 17}{10}\ yards

Total\ length\ of\ fabric\ sue\ buys = \frac{85}{10}\ yards

In the decimal form

Total length of fabric sue buys = 8.5 yards

As given

One yard of the fabric costs $5

Total\ cost\ of\ fabric\ sue\ buys = 8.5\times 5

                                                            = $ 42.5  

Therefore the total length of fabric sue buys is 8.5 yards and total cost of the fabric is $42.5 .


5 0
3 years ago
La profesora de matemáticas solicita a dos estudiantes que describan las cosas que les han parecido interesantes de los números
Makovka662 [10]

Answer:

Respuesta D

Step-by-step explanation:

Paola afirma: Todo número compuesto par, se puede escribir como la multiplicación de factores primos.

Esta afirmación es cierta, pues es un caso  de la afirmación de que todo número natural mayor que uno se puede escribir como multiplicación de números primos. A este proceso se le llama descomposición en factores primos.

Edwin afirma: Todo número compuesto impar se puede escribir como la suma de dos números primos.

Esta afirmación es falsa. Note que al sumar dos números impares de la forma 2k+1 y 2m+1 para k distinto de m, se obtiene

2k+1+2m+1 = 2(km+1)

Es decir, la suma de dos números impares es siempre par.

Note que a excepción de 2, todo número primo es impar. Para que esta afirmación fuera cierta, necesariamente tendría que pasar que cualquier número impar k se escriba de la forma p+2 donde p es un número primo. Esto es equivalente que para cualquier número impar k, el número k-2 sea primo.

Basta con dar un ejemplo para ver que esto no pasa. Tomemos k=11. En este caso, k-2 = 9, el cuál no es un número primo. Entonces 11 no se puede  descomponer como la suma de dos números primos.

5 0
3 years ago
Help please i need help if i get this one wrong i need to start over
earnstyle [38]

Answer:

Step-by-step explanation:

Right/left by 3 units because in the equation, it added 3. Right because it is positive and Right/Left because this represents the change in the x-axis.

Up/Down by 5 units because in the equation, it added 5. Up because it is positive and Up/Down because this represnts  the change in the y-axis.

6 0
3 years ago
Prove 2√(x) + 1/√(x + 1) <= 2√(x+1) for all x in [0,inf)
EleoNora [17]
Start by multiplying each side of the inequality by \sqrt{x + 1} and simplifying:

2 \sqrt x + \frac{1}{\sqrt{x+1}}  \leq  2 \sqrt{x + 1}
(2 \sqrt x + \frac{1}{\sqrt{x+1}})(\sqrt{x + 1}) \leq (2 \sqrt{x + 1})(\sqrt{x + 1})
2 \sqrt{x(x + 1)} + 1 \leq 2(x + 1)
2 \sqrt{x^2 + x} + 1 \leq 2x + 2
2 \sqrt{x^2 + x} \leq 2x + 1
\sqrt{x^2 + x} \leq x + \frac{1}{2}

From here, we can square both sides to get

x^2 + x \leq (x + \frac{1}{2})^2
x^2 + x \leq x^2 + x + \frac{1}{4}
0  \leq \frac{1}{4}, which is always true.
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Answer:

lil shawty

Step-by-step explanation:

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