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algol13
4 years ago
13

What is 50% of 42.88 ?

Mathematics
1 answer:
Bingel [31]4 years ago
6 0

Answer:

21.44

Step-by-step explanation:

50% = 1/2

1/2 of 42.88

42.88 ÷ 2

21.44

Hope this helps :)

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Ratio of boys to girls is 2:3 what is the ratio of boys of there are 6 girls​
Mama L [17]

Answer:

4:6

Step-by-step explanation:

2 x

- = ----

3 6

6/3 = 2

2 x 2 = 4

7 0
3 years ago
Plz help me fast. I'll give 5 points ​
lidiya [134]
A parallelogram has two pairs of opposite equal angles.
ABCD so
A = C and B = D

A = 2x + 35
C = 3x - 5

2x + 35 = 3x - 5
35 + 5 = 3x - 2x
40 = x

A = (2 x 40) + 35 = 115
A = C = 115

Sum of angles of a quadrilateral = 360

Angles B and D are equal
So
B = (360 - (115 + 115))/ 2
= 130/2
= 65

B = D = 65
6 0
3 years ago
Sue's car used 12 gallons of gas on a 300 mile trip. Jen's car used 5 gallons of gas on a 140 mile trip. Whose car got more mile
vekshin1
Jen's car because if you divide 140 by 5 you get 28 and that's 28 miles per gallon. When you divide 300 by 12 you get 25 and that's 25 miles per gallon.
8 0
3 years ago
Read 2 more answers
A species of phytoplankton measures about 2 × 10−6 in. A grain of sand measures about 1 × 10−4 in. About how many times longer i
taurus [48]

Answer : The grain of sand is 50 times greater than the phytoplankton.

Step-by-step explanation :

As we are given that:

Size of phytoplankton = 2 × 10⁻⁶ in

Size of sand grain = 1 × 10⁻⁴ in

Now we have to determine how many times longer the grain of sand is than the phytoplankton.

We are dividing the sand grain size by the phytoplankton size.

This can be done by equating it as follows:

\frac{\text{Size of sand grain}}{\text{Size of phytoplankton}}=\frac{1\times 10^{-4}in}{2\times 10^{-6}in}

\frac{\text{Size of sand grain}}{\text{Size of phytoplankton}}=50

Therefore, the grain of sand is 50 times greater than the phytoplankton.

5 0
3 years ago
Help me quick please.
Rudiy27

Answer:

No, the answer is not reasonable. It should be about 1 foot

Step-by-step explanation:

we know that

The correct dimensions are

Gina had two pieces of ribbon. One was 5/8  foot long and the other was 1/4  foot long

so

Sum the length of both pieces

\frac{5}{8}+\frac{1}{4}=\frac{5+2}{8}=\frac{7}{8}\ ft

\frac{7}{8}\ ft< 1\ ft

therefore

No, the answer is not reasonable. It should be about 1 foot

3 0
4 years ago
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