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Karo-lina-s [1.5K]
3 years ago
6

Answer a and b ASAP

Mathematics
1 answer:
melomori [17]3 years ago
6 0

Answer:

The area of the rectangle is 48cm2

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Hi guys, can you please help me with this?
Digiron [165]

Answer:

see explanation

Step-by-step explanation:

Expand the right side and then compare like terms with the left side.

(q + 2\sqrt{3} )²

= q² + 4q\sqrt{3} + 12

= q² + 12 + 4q\sqrt{3}

Compare like terms with 28 + p\sqrt{3}

Comparing the \sqrt{3} terms gives

p = 4q

and comparing the constant terms gives

q² + 12 = 28 ( subtract 12 from both sides )

q² = 16 ( take the square root of both sides )

q = ± \sqrt{16} = ± 4

Hence

p = 4q = 4 × ± 4 = ± 16

4 0
3 years ago
Let u = 5, -12 and c = -3. What is cu?
BigorU [14]
If u =5 and c= -3 then cu = -3+5 = 2 
3 0
3 years ago
Read 2 more answers
If You were given f (3)=7, what is the x value
Ede4ka [16]

Answer:

7/3

Step-by-step explanation:

divide each term by 3 and simplify

5 0
3 years ago
A rectangle is measured 6.5 cm by 7.8 cm .
mote1985 [20]

Answer:

3.24%

Step-by-step explanation:

Percentage error =[ (|calculated value  - actual value) / actual value] x 100

calculated area = length x width

6.5 x 7.8 = 50.7

[(|50.7 - 52.4|] / 52.4] x 100 = 3,24

7 0
3 years ago
Please help meeeeee I will mark you!.<br><br> I need an answer and explanation
kari74 [83]

Answer:

<em>12^2 + x^2 = 13^2</em>

Step-by-step explanation:

The student's error was that he didn't use the Pythagorean Theorem correctly

According to the Pythagorean Theorem, <em>a^2 + b^2 = c^2</em>, where c represents the hypotenuse

However, the student replaced <em>c</em> with <em>x</em>, which isn't the hypotenuse

The hypotenuse is 13, so <em>c</em> should be 13, not <em>x</em>

5 0
3 years ago
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