8p² - 16p = 10
8p² - 16p - 10 = 0 Divide through by 2
4p² - 8p - 5 = 0
Multiply first and last coefficients: 4*-5 = -20
We look for two numbers that multiply to give -20, and add to give -8
Those two numbers are 2 and -10.
Check: 2*-10 = -20 2 + -10 = -8
We replace the middle term of -8p in the quadratic expression with 2p -10p
4p² - 8p - 5 = 0
4p² + 2p - 10p - 5 = 0
2p(2p + 1) - 5(2p + 1) = 0
(2p + 1)(2p - 5) = 0
2p + 1 = 0 or 2p + 5 = 0
2p = 0 -1 2p = 0 - 5
2p = -1 2p = -5
p = -1/2 p = -5/2
The solutions are p = -1/2 or -5/2
<span>First of all to calculate the distance between two points we can use distance formula
d=Square Root [(x2-x1)^2 + (y2-y1)^2]
Now substitute the given points p(x1,y1) and q(x2,y2)in above distance formula
The values are X2=3, X1=8and Y2=8and Y1=2.
After Substituting the values
d=Square Root[(-5)^2+(6)^2]
d=Square Root(25+36]
d=Square Root[61]
d=7.8
7.8 is the distance between points P(8, 2) and Q(3, 8) to the nearest tenth.</span>
Answer:
yeah
Step-by-step explanation:
I failed 3rd grade
Answer:
Step-by-step explanation:
(-9-7)/(0-1)= -16/-1= 16
y - 7 = 16(x - 1)
y - 7 = 16x - 16
y = 16x - 9
To rotate a figure
90 degrees(-y,x)
180 degrees(-x,-y)
270 degrees(y,-x)
If your original point is (1,2) or example and you want to rotate it say 270 degrees the final point would be (2,-1)
Hope this helped!!!!!
