Answer:
B. High optical density, and light travels more slowly through it.
Step-by-step explanation:
Refractive index is the property of a material that describes the change in the initial path of light and the rate at which light travels through it. And optical density of a material describes its absorption ability to rays or beam of light passing through it.
As the index of refraction of a material increases, therefore its optical density would increase. This would cause light to travel through it slowly. Unless the light has a high frequency.
A material with a high index of refraction has a high optical density, and light travels more slowly through it.
Answer:
1). Option B.
2). Option C.
3). Option A.
4). Option C.
5). Option D.
6). Option C.
Step-by-step explanation:
1). Bisector of angle ABC is,
Option (B). stack BD with rightwards arrow on top.
2). Since GH = GI [Given]
3x = 5x - 10
5x - 3x = 10
2x = 10
x = 5
Therefore, GH = 3x
= 3(5)
= 15
Option (C). is the answer.
3). Since m∠ABD ≅ m∠DCB [Given]
and m∠DCB ≅ m∠CBE [Since GH ≅ GI]
Therefore, m∠ABD ≅ m∠CBE
10y = 8y + 4
10y - 8y = 4
2y = 4
y = 2
Option (A). is the answer.
4). m∠DBE = m∠DBC + m∠CBE
= 10y + (8y + 4)
= (18y + 4)°
By putting y = 2,
m∠DBE = 18×2 + 4
= 36 + 4
= 40°
Option (C) will be the answer.
5). m∠ABE = m∠ABD + m∠DBC + m∠CBE
= 10y + 10y + (8y + 4)
= 28y + 4
= 28×2 + 4
= 56 + 4
= 60°
Option (D) will be the answer.
6). If m∠FBA = 7x + 6y
By putting x = 5 and y = 2
m∠FBA = 7(5) + 6(2)
= 35 + 12
= 47°
Option (C) will be the answer.
Answer:
f(3) = 3
Step-by-step explanation:
(1) = 1
f(2)= 2
(f(n) = f(n − 2) + f(n-1)
f(3) =f(3 − 2) + f(3-1)
= f(1) + f(2)
= 1 + 2
= 3
3m-3.
basically since 6 and -9 don’t have any variables, you would ignore the 3m to combine them like 6-9, which would be -3 and then adding that onto the 3m you would get 3m-3