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3 years ago

I am a two digit number

Mathematics

1 answer:

Radda [10]3 years ago

4 0

I think 14, because 7-3=4 and then 10+4= and even number

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A spa employs 54 people. Management wants to gather data about current and future services for clients. A random sample of 22 em

Igoryamba

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Step-by-step explanation:

i choose (c) because that the answer

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3 years ago

Which of the following represents a problem that could be solved by the

gregori [183]

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3 years ago

Joe has a bag of blocks. 3 red blocks and 2 blue blocks weigh 24 ounces while 1 red block and 3 blue blocks weigh 16 ounces. Def

fredd [130]

Answer: 3r + 2b = 24

r + 3b = 16

Step-by-step explanation:

Let the red blocks be represented by r

Let blue blocks be represented by b

Since 3 red blocks and 2 blue blocks weigh 24 ounces. This will be:

3r + 2b = 24

1 red block and 3 blue blocks weigh 16 ounces. This will be:

r + 3b = 16

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3 years ago

Ayush scored 720 marks out of900. And his brother scored 630 out of 700. whose perfomance is better

tresset_1 [31]

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8 0

3 years ago

Read 2 more answers

Which is the equation of a hyperbola centered at the origin with x-intercept +\- 3 and asymptote y=2x

Radda [10]

Answer:

${\dfrac{x^{2}}{9} - \dfrac{y^{2}}{36} = 1}$

Step-by-step explanation:

The hyperbola has x-intercepts, so it has a horizontal transverse axis.

The standard form of the equation of a hyperbola with a horizontal transverse axis is $\dfrac{(x - h)^{2}}{a^{2}} - \dfrac{(y - k)^{2}}{b^{2}} = 1$

The center is at (h,k).

The distance between the vertices is 2a.

The equations of the asymptotes are $y = k \pm \dfrac{b}{a}(x - h)$

1. Calculate h and k. The hyperbola is symmetric about the origin, so

h = 0 and k = 0

2. For 'a': 2a = x₂ - x₁ = 3 - (-3) = 3 + 3 = 6

a = 6/2 = 3

3. For 'b': The equation for the asymptote with the positive slope is

$y = k + \dfrac{b}{a}(x - h) = \dfrac{b}{a}x$

Thus, asymptote has the slope of

$\begin{array}{rcl}m& =& \dfrac{b}{a}\\\\2& =& \dfrac{b}{3}\\\\b& =& \mathbf{6}\end{array}$

4. The equation of the hyperbola is

$\large \boxed{\mathbf{\dfrac{x^{2}}{9} - \dfrac{y^{2}}{36} = 1}}$

The attachment below represents your hyperbola with x-intercepts at ±3 and asymptotes with slope ±2.

7 0

3 years ago