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3 years ago

Find the product and simplify your answer -4a^4(9a^2-8)

Mathematics

1 answer:

Hunter-Best [27]3 years ago

4 0

Answer: -36a^6+32a^4

Step-by-step explanation:

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Please help I don't understand T^T

yarga [219]

Answer:

I can't see the picture

Step-by-step explanation:

Are you sure that you uploaded it?

5 0

4 years ago

Read 2 more answers

Alexander and Matthew go to the movie theater and purchase refreshments for their friends. Alexander spends a total of $60.00 on

soldi70 [24.7K]

Answer:

2x + 9y = 60

10x + 5y = 60

The price of each bag of popcorn is $6.

Step-by-step explanation:

Let each drink costs $x and the price of each bag of popcorn is $y.

So, from the given two conditions we can write two different equations as

2x + 9y = 60 ............... (1) and

10x + 5y = 60 ................. (2)

Now, solving those two equations we get,

5(60 - 9y) + 5y = 60

⇒ 300 - 45y + 5y = 60

⇒ 40y = 240

⇒ y = 6

Therefore, the price of each bag of popcorn is $6. (Answer)

3 0

3 years ago

At halloween 3/10 of the candy robin receivd was chocolate. what percent of candy was chocolate,

Tomtit [17]

If 3/10 was chocolate
3/10=0.3
0.3 *100=30% was chocolate

4 0

4 years ago

Write an inequality and solve the problem the sum of a number and 19 is at least 8.2.

Sunny_sXe [5.5K]

When you write it as an inequality you get x + 19 ≈ 8.2 and when you solve it it should look like x + 19 ≈ 8.2
19 ≈ - 19
 x ≈ -10.8

4 0

3 years ago

If RX=4 and XS=9, then XT= And how do you get it?

konstantin123 [22]

Answer:

XT=6 units

Step-by-step explanation:

The picture of the question is the attached figure

step 1

In the right triangle RST

Applying the Pythagorean theorem

$RS^2=RT^2+TS^2$

we have

$RS=RX+XS=4+9=13\ units$ ---> by segment addition postulate

substitute

$RT^2+TS^2=169$ ----> equation A

step 2

In the right triangle RTX

Applying the Pythagorean theorem

$RT^2=RX^2+XT^2$

we have

$RX=4\ units$

substitute

$RT^2=4^2+XT^2$

$RT^2=16+XT^2$

$XT^2=RT^2-16$ ----> equation B

step 3

In the right triangle XTS

Applying the Pythagorean theorem

$TS^2=XS^2+XT^2$

we have

$XS=9\ units$

substitute

$TS^2=9^2+XT^2$

$TS^2=81+XT^2$

$XT^2=TS^2-81$ ----> equation C

step 4

equate equation B and equation C

$TS^2-81=RT^2-16$

$TS^2-RT^2=81-16$

$TS^2-RT^2=65$ ----> equation D

step 5

Solve the system

$RT^2+TS^2=169$ ----> equation A

$TS^2-RT^2=65$ ----> equation D

Solve by elimination

Adds equation A and equation D

$RT^2+TS^2=169\\TS^2-RT^2=65\\---------\\TS^2+TS^2=169+65\\2TS^2=234\\TS^2=117$

Find the value of RT^2

$RT^2+117=169\\RT^2=52$

step 6

Find the value of XT

equation C

$XT^2=117-81\\XT^2=36\\XT=6\ units$

7 0

3 years ago