Answer:
That A Newborn Fawn Is Randomly Selected. Round All Answers To Two Decimal Places A. The Mean Of This Distribution Is B. The Standard Deviation Is C. The Probability That The Fawn Will Weigh More Than 2.8 Kg. D. Suppose That It Is Known That The Fawn Weighs Less
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Suppose that the weight of an newborn fawn is uniformly distributed between 2 and 4 kg. Suppose that a newborn fawn is randomly selected. Round all answers to two decimal places
A. The mean of this distribution is
B. The standard deviation is
C. The probability that the fawn will weigh more than 2.8 kg.
D. Suppose that it is known that the fawn weighs less than 3.5 kg. Find the probability that the fawn weights more than 3 kg.
E. Find the 90th percentile for the weight of fawns.
Explanation:
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Answer:
0.04 *60,0000= 2400
Debt Credit
Bad debt expense 2400
Accounts receivables 2400
Allowance for doubtful accounts 2400
Bad dent expense 2400
Explanation:
Answer:
$201,700
Explanation:
The budget production for May is 5000 units.
The total materials required for May will be no. of units multiplied by materials needed for each unit
=5000 x 3
=15000 pounds of materials
Materials required for June
=60% of (4400x 3)
= 60/100 x 13200
=7920 pounds of material
Total materials needed for May
= 15,000+7,920
=22,920 pounds
Purchases required will be
=22,920 - 2,750
=20170
Purchases in dollar value =20170 x $10
=$201,700
Answer:
The correct answer is (2)The workers on shop floor lack the autonomy to stop the manufacturing on their own initiative.
Explanation:
The company operates on a push system, where products are made and inventory built up based on best-guess forecasts.
The push system of inventory control involves forecasting inventory needs to meet customer demand. Companies must predict which products customers will purchase along with determining what quantity of goods will be purchased.
So, from the given options, the correct answer is (2)The workers on shop floor lack the autonomy to stop the manufacturing on their own initiative