Question

Ann and betty together have $60. Ann has $9 more than twice Bettys amount. How much do each have?

Answer 1

Answer:

• Ann: $43
• Betty: $17

Step-by-step explanation:

Let b represent the amount Betty has. Then Ann has 2b+9 and together, they have ...

  b + (2b+9) = 60

  3b = 51 . . . . . . . . . subtract 9

  b = 17 . . . . . . . . . .  divide by 3

Betty has $17 and Ann has the other $43 of the total of $60.

Answer 2

Answer:

Ann = 34 while betty has 17

Step-by-step explanation:

let betty be y

let Ann be 2y, having $9 extra,

Ann will be 2y + $9

Ann and betty = $60

2y + $9 + y = $60

2y + y = $60 - $9

3y =  $51

y = 51/3

y= 17

since Ann is 2y+9 and Betty is y

Ann = 2(17) + 9 while betty is 17

Ann = 34+9 and betty = 17

Ann = 43 and betty = 17