2x - 3y = 8 is the equation of the line that passes through the point (1,-2) and is parallel to the line passing through the point (-2,-1) and (4,3)
<em><u>Solution:</u></em>
We have to find the equation of the line that passes through the point (1, -2) and is parallel to the line passing through the point (-2, -1) and (4, 3)
Let us first find the slope of line
We know slope of a line and slope of line parallel to it are equal
So we can find the slope of line passing thorugh the point (-2, -1) and (4, 3)
<em><u>The slope of line is given as:</u></em>
The points are (-2, -1) and (4, 3)
Substituting the values we get,
Thus the slope of line passing thorugh the point (-2, -1) and (4, 3) is
So the slope of line parallel to it also
Now find the equation of the line that passes through the point (1, -2) with slope
<em><u>The equation of line in slope intercept form is given as:</u></em>
y = mx + c ---- eqn 1
Where "m" is the slope of line and c is the y - intercept
Substitute (x, y) = (1, -2) and in eqn 1
Writing in standard form, we get
Thus the equation of line is found