Answer:
D 7
Step-by-step explanation:
Total no. of bulb= 5
no. of defected bulb= 3
no. of not defected bulb=2
Total no. of bulb combination = 5C2
=5!/2!(5-2)!
= 5!/2!3!
= 5×4×3×2×1/2×1×3×2×1
=120/12
=10
( since a room can be lighted with one bulb also)
total no. of bulb combination when room shall not light = 3C2
3!/2!(3-2)!
= 3!/2! 1!
= 3×2×1/2×1×1
= 6/2
=3
Now,
Total no. of trial when room shall light
=10-3
=7
Hence, number of trial when the room shall be lighted is 7 which is option d
Answer:
11. B.
12. 3
Step-by-step explanation:
![\sqrt[3]{27}=3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%3D3)
since 
1- y= x/2 + 2
2- y= 3x +1
3- y= x/2 - 2
4- y= 3x - 1
Answer:
Step-by-step explanation:
tan(30°) = 
cot(30°) = 
sin(60°) = 
Answer:
6250
Step-by-step explanation:
Hope the answer is correct.
