Answer:
Explanation:
Both ranges <em>ABUT </em> at their <em>eastern </em>or E.N.E
I'd like to follow up with an <em>ANTECEDENT </em>question for the reporter
It is his sacred duty and his private interest to <em>BEGET</em> children and to train them to take his place
When you use a baseball bat to beat someone until he is unconscious, this is an example of when you <em>BLUDGEON</em> him.
Her thoughts were interrupted by a <em>CACOPHONY </em>of a sound, I heard a voice call out in agony.
The harbour is <em>CAPACIOUS</em> and secure, with a sufficient depth of water for the largest vessels.
Music is a means of <em>CATHARSIS</em> for her.
Her <em>COTERIE</em> of fellow musicians His films are admired by a small <em>COTERIE</em> of critics.
Only a <em>DEMAGOGUE </em>could persuade so many people to rebel against authority.
Even his misanthropy is only an inverted form of social solicitude. Her books are a sovereign remedy for depression and misanthropy.
Assuming your interest rate on the loan is 8. 6%. The additional margin generated will cover the interest payments.
<h3>Additional margin</h3>
Let determine the weekly interest
Weekly interest= 8.6% /12 x 60,000
Weekly interest= $99.23
Let calculate the amount left since the business generates $500 at a margin of 80
Amount left= 500 x 80%
Amount left= $400
Based on the above calculation we can see that the amount of $400 is sufficient enough to cover the $99.23 payments.
Inconclusion the additional margin generated cover the interest payments.
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Arguments, poor communication skills
A shaft seal, because its the top part
How thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.
<h3>Density of the Neutron star</h3>
Density
ρ = m / V
Where:
ρ= density
m = mass of the planet 5.98 10²⁴ km
V =volume of the spherical layer
Volume of a sphere
Volume = 4/3 π r³
Mass = 1.5 = 1.5 1,991 10³⁰
Mass= 2.99 10³⁰ kg
Density:
ρ = 2.99 10³⁰ / [4/3 π (10 10³)³]
ρ is = 7.13 10 17 kg / m³
V = 5.98 10²⁴ / 7.13 10¹⁷
V = 8,387 10⁶ m³
Thickness of the layer
V = 4π r² e
e = V / 4π r
e = 8,387 10⁶ / [4π (10 10³)²]
e = 6.67 10⁻³ m
Inconclusion how thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.
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