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Anna007 [38]
3 years ago
10

Write the ratio $12 dollers for 3 tickets as a unit rate​

Mathematics
1 answer:
guajiro [1.7K]3 years ago
8 0

The unit rate would be the price for 1 ticket.

12 dollars / 3 tickets = $4 per ticket.

The ratio would be 4:1

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leva [86]

Answer:

a=108

Step-by-step explanation:

180x3=540

540/5=108

a=108˚

6 0
3 years ago
What is parallel to 2x-y=1 and contains (4, -6)? Please show your work!
Contact [7]

k:\ y=m_1x+b_1\\\\l:\ y=m_2x+b_2\\\\l\ ||\ k\iff m_1=m_2\\\\\text{We have}\\\\k:\ 2x-y=1\ \ \ |-2x\\-y=-2x+1\ \ \ \ |\cdot(-1)\\y=2x-1\to m_1=2\\\\l:\ y=m_2x+b\\\\l\ ||\ k\iff m_2=2\\\\l:\ y=2x+b\\\\\text{The line l contains (4, -6)}\\\\\text{Put the values of coordinates to the equation of line l}\\\\-6=2(4)+b\\-6=8+b\ \ \ \ \ |-8\\b=-14\\\\Answer:\ y=2x-14\to 2x-y=14

5 0
3 years ago
Determine whether the improper integral converges or diverges, and find the value of each that converges.
Ksju [112]

Answer:converge at I=\frac{1}{3}

Step-by-step explanation:

Given

Improper Integral I is given as

I=\int^{\infty}_{3}\frac{1}{x^2}dx

integration of \frac{1}{x^2}  is  -\frac{1}{x}

I=\left [ -\frac{1}{x}\right ]^{\infty}_3

substituting value

I=-\left [ \frac{1}{\infty }-\frac{1}{3}\right ]

I=-\left [ 0-\frac{1}{3}\right ]

I=\frac{1}{3}

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8 0
3 years ago
A rectangular filed is 190m by 270m . A rectangular barn is 23 m by 40 m is built in the field .
Anika [276]

Answer: 50,380m

Step-by-step explanation:

190m * 270m = 51,300m

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Because the barn is in the field, we subtract the barn's area from the field's area, which leaves us with

51,300m - 920m = 50,380m

4 0
3 years ago
Exhibit 6-5 The weight of items produced by a machine is normally distributed with a mean of 8 ounces and a standard deviation o
hjlf

Answer:

46.18% of the items will weigh between 6.4 and 8.9 ounces.

Step-by-step explanation:

We are given that the weight of items produced by a machine is normally distributed with a mean of 8 ounces and a standard deviation of 2 ounces.

<em>Let X =  weight of items produced by a machine</em>

The z-score probability distribution for is given by;

                Z = \frac{  X -\mu}{\sigma}  ~ N(0,1)

where, \mu = mean weight = 8 ounces

            \sigma = standard deviation = 2 ounces

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, percentage of items that will weigh between 6.4 and 8.9 ounces is given by = P(6.4 < X < 8.9) = P(X < 8.9 ounces) - P(X \leq 6.4 ounces)

   P(X < 8.9) = P( \frac{  X -\mu}{\sigma} < \frac{  8.9-8}{2} ) = P(Z < 0.45) = 0.67364  {using z table}

   P(X \leq 70) = P( \frac{  X -\mu}{\sigma} \leq \frac{  6.4-8}{2} ) = P(Z \leq -0.80) = 1 - P(Z < 0.80)

                                                 = 1 - 0.78814 = 0.21186

<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.45 and x = 0.80 in the z table which has an area of </em>0.67364<em> and </em>0.78814<em> respectively.</em>

Therefore, P(6.4 < X < 8.9) = 0.67364 - 0.21186 = 0.4618 or 46.18%

<em>Hence, 46.18% of the items will weigh between 6.4 and 8.9 ounces.</em>

8 0
3 years ago
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