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frozen [14]
3 years ago
8

Find the surface areas of sphere with a radius of 100 ydz

Mathematics
1 answer:
PtichkaEL [24]3 years ago
8 0
We know that

[surface area of sphere]=4*pi*r²
for r=100 yd
[surface area of sphere]=4*pi*100²-----> 40000*pi yd²

the answer is
40000*pi yd²
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The difference of two perfect cubes is 386. If the cube root of the smaller of the two numbers is 7, then the cube root of the l
choli [55]

Answer:

9

Step-by-step explanation:

Let the two perfect cubes be x and y where x > y.

According to the given conditions:

{x}^{3}  -  {y}^{3}  = 386...(1) \\ y = 7...(2) \\ plug \: y = 7 \: in \: equation \: (1) \\  {x}^{3}  -  {7}^{3}  = 386 \\ {x}^{3}  -  343 = 386 \\ {x}^{3}     = 343  +  386 \\ {x}^{3}     = 343  +  386 \\ {x}^{3}   = 729 \\ x =  \sqrt[3]{729}  \\ x = 9

Thus the cube root of the larger number is 9.

8 0
3 years ago
Write each decimal as a fraction <br> .07<br> .051<br> .473<br> .27<br> .5.37<br> .16.49
Colt1911 [192]

Answer:

7/10

51/100

473/1000

27/100

537/1000

1649/10000

Step-by-step explanation:

im curious about what the dots are in .16.49 and .5.37, why are there two dots?

3 0
2 years ago
Solve the equation. z/32 + 5/8 =13/16<br><br> True Or false, And why?
Oxana [17]
The equation is false because the real answer is z5/4. The variable doesn't just disappear.
5 0
3 years ago
Read 2 more answers
What is the nth term rule of the quadratic sequence below?<br> 8,14,22,32 ,44, 58, 74...
DanielleElmas [232]

Answer:

y=n^2+3n+4

Step-by-step explanation:

Sequence,S: 8,14,22,32 ,44, 58, 74...

First differences of S: 6,8,10,12,14,16,...

Second differences of S: 2,2,2,2,2,2,....

It is indeed a quadratic since the 1st differences that are the same are the second differences.

So the 1st term is 8. If the 0th term was listes it would be 4 since 8-4=4 and 6-4=2.

This means our quadratic it is in the form

y=an^2+bn+c where c=4.

So we have y=an^2+bn+4.

Now we can find a and b using two points from our sequence to form a system of equations to solve.

(1,8) gives us 8=a(1)^2+b(1)+4

Simplifying gives 8=a+b+4

Subtracting 4 on both sides gives: 4=a+b

(2,14) gives us 14=a(2)^2+b(2)+4

Simplifying gives 14=4a+2b+4

Subtracting 4 on both sides gives 10=4a+2b

So we have the following system to solve:

4=a+b

10=4a+2b

I'm going to solve using elimination/linear combination style.

Dividing second equation by 2 gives the system as:

4=a+b

5=2a+b

Subtract the 2nd equation from the first gives:

-1=-1a

This implies a=1 since -1=-1(1) is true.

If a+b=4 and a=1, then b=3. Because 3+1=4.

So the equation is y=1n^2+3n+4 or y=n^2+3n+4.

8 0
3 years ago
Choose all that correctly solve for x.
Tamiku [17]

Answer:

Options: A, B, and C correctly solve for x.

Step-by-step explanation:

A).

\frac{5}{2} x = \frac{15}{2}

Multiplying both sides by 2 gives;

5x = 15

x = 15 ÷ 5 = 3

∴ This option correctly solve for x.

B).

x + \frac{7}{2} = 7

x = 7 - \frac{7}{2} = \frac{14}{2} -\frac{7}{2} = \frac{7}{2}

∴ This option correctly solve for x.

C).

x + 3 = \frac{21}{5}

x = \frac{21}{5} - \frac{15}{5}  = \frac{6}{5}

But the option give x as 5/6 hence this option does not correctly solve for x.

D).

5x = 11/2

x = 11/2 ÷ 5 = 11/2 × 1/5 = 11/10

But the option gives x as 10/11 so it does not correctly solve for x.

8 0
3 years ago
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