Answer:
<em>72,000cm³</em>
Step-by-step explanation:
Volume of the rectangular tank = Length * Width * Height
Given
Length = 50cm
Width = 30cm
Height = 60cm
Get the volume:
Volume = 50*30*60
Volume = 90,000cm³
Hence the volume of the rectangular tank is 90,000cm³.
If 1/5 of the volume of water was transferred to another tank, the volume transferred will be:
Amount transferred = 1/5 * 90,000
Amount transferred = 18000cm³
Amount left in the tank = 90,000 - 18,000
<em>Amount of water left in the tank = 72,000cm³</em>
Answer:
0.56
Step-by-step explanation:
There are 14 girls, and a total of 25 students. So the probability of selecting a girl is P = 14/25 = 0.56.
Solve for v by simplifying both sides of the equation, then isolating the variable.
v = -1
Answer:
There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
is the Euler number
is the mean in the given time interval.
The problem states that:
The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and mean 0.2 each day during the weekend.
To find the mean during the time interval, we have to find the weighed mean of calls he receives per day.
There are 5 weekdays, with a mean of 0.1 calls per day.
The weekend is 2 days long, with a mean of 0.2 calls per day.
So:

If today is Monday, what is the probability that Ben receives a total of 2 phone calls in a week?
This is
. So:


There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.
Answer:
It will take 88.2 months to accumulate the amount
Step-by-step explanation:
Given;
Future value of money, FV = $25,000
investment per compound period, P = $200
interest rate, i = 0.75% x 12 = 9%
The number of monthly installments required to amount to FV is given by;

Therefore, it will take 88.2 months to accumulate the amount.