The best describe the future of cybersecurity is strong security policies offer little protection.
<h3>What is cybersecurity?</h3>
Cybersecurity is the security of data or computer systems. Cybersecurity is provided from the hackers that hacks the data and money online.
As everything is converting digital, the need of cybersecurity is increasing.
Thus, the correct option is B.
Learn more about cybersecurity
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Answer: Compatibility
Explanation:
According to the question, the given products are offering compatibility with the customers needs and the priorities of the consumers. The customers comparability means the degree of the product that fit between customers expectation and the capability of serving by the operation team.
The customers expectation mainly reflected both the present and the past evaluation of the products and the user experience. The compatibility of the customers needs is to meet the quality, value and the service of the product.
The reason for analyzing an algorithm is to discover its characteristics in order to evaluate its suitability for various applications are compared with other algorithms for the same application
The doors can be pushed shut from the outside. There is either a latch where they can be locked with a padlock, or there is an access port near the door where they can be locked with a key.
// Writing a C++ Program for the given senario
#include<iostream> // Using input and output stream
using namespace std; // Using standard namespace
// Main function
int main(){
int num = 10; // int num initialized with 10
double cost =1000; // double cost initialized with 1000
/*
Cout is stream in C++ that uses << symbol to output anything on the screen and as the problem says we need to output both numbers on a line, i have used multiple << because on cout streams you are allowed to send one element at a time.
Also, endl is a keyword in C++ that ends the line after output for the cout stream is finished.
*/
cout<< num << " " << cost <<endl;
// Return 0 means telling the compiler to terminate the //program
return 0;
}
