<span>x^2 + 8x = -3
</span><span>x^2 + 8x + 16 = -3 + 16
using a^2 + 2 a b + b^2 = (a+b)^2
</span><span>
</span>x^2 + 8x + 16 = 13
<span>(x +4)^2 = 13
answer : 16 is the number </span><span>you must add to complete the square</span>
Given :
Center of sphere , C( 1 , -1 , 6 ) .
To Find :
Find equations of the spheres with center (1, −1, 6) that touch the following planes.a) xy-plane b) yz-plane c) xz-plane .
Solution :
a)
Distance of the point from xy-plane is :
d = 6 units .
So , equation of circle with center C and radius 6 units is :

b)
Distance of point from yz-plane is :
d = 1 unit .
So , equation of circle with center C and radius 1 units is :

c)
Distance of point from xz-plane is :
d = 1 unit .
So , equation of circle with center C and radius 1 units is :

Hence , this is the required solution .
Answer:
This nijja sucks at his job dont listen
Step-by-step explanation:
Fok you all bithces
all real numbers is the domain of the function y=x+4
Chapter : Linear equations
Lesson : Math for Junior High School
7x + 14y = 28
if want to find x and y, we must substitution value 0 to the equation x and y :
# If x = 0, then :
7x + 14y = 28
= 7(0) + 14y = 28
= 0 + 14y = 28
= 14y = 28 → y = 28/14
= y = 2
# If y = 0, then :
7x + 14y = 28
= 7x + 14(0) = 28
= 7x + 0 = 28
= 7x = 28 → x = 28 / 7
= x = 4
and that result was proven x = 4 and y = 2