PLEASE HELP THANK YOU IN ADVANCE NEED TO SUBMIT SOON!! PLEASE PLEASE PLEASE HELP

1 answer:

6 0

Provate school in 2005
f(t)=85+18t

public school
g(t)=95+15t

graph
easy
replace g(t) and f(t) with y
y=18t+85
y=15t+95
input values for t and get values for y

y=18t+85
when t=0 y=85
when t=1 y=103
plot the oints (0,85) and (1,103)

y=15t+95
if t=0 then y=95
if t=1 then y=110
plot the points (0,95) and (1,110)

the easier way would just to be to solve the equatons but anyway
interscection point is (3 and 1/3,145)

so after 3 years (2008) it is about 145

You might be interested in

Nent

STatiana [176]

7^2/7^-2 and (7^2)^2

7 0

3 years ago

The width of a rectangle measures (2h-6) centimeters, and its length measures (7h+8) centimeters. Which expression represents th

dedylja [7]

Answer:

18h +4

Step-by-step explanation:

The perimeter of a rectangle is given by

P = 2(l+w) where l is the length and w is the width

=2( 7h+8 + 2h-6)

Combine like terms

= 2( 9h+2)

Distribute

= 18h +4

4 0

2 years ago

The bus arrived at 8:20. It left 30 minutes earlier. What time did the bus leave?

OlgaM077 [116]

7:50 AM /PM is the time

6 0

3 years ago

Read 2 more answers

Find the right quotient. 36m 5 n 5 ÷ (12m 3)

polet [3.4K]

ANSWER

The right quotient is

$3 {m}^{2} {n}^{5}$

EXPLANATION

The given expression is :

$\frac{36 {m}^{5} {n}^{5} }{12 {m}^{3} }$

$\frac{36 {m}^{5} {n}^{5} }{12 {m}^{3} } = \frac{36}{12} \times \frac{ {m}^{5} }{ {m}^{3}} \times {n}^{5}$

$\frac{36 {m}^{5} {n}^{5} }{12 {m}^{3} } = 3\times \frac{ {m}^{5} }{ {m}^{3}} \times {n}^{5}$

Recall that,

$\frac{ {a}^{m} }{ {a}^{n} } = {a}^{m - n}$
We apply this property to obtain;

$\frac{36 {m}^{5} {n}^{5} }{12 {m}^{3} } = 3 \times {m}^{5 - 3} \times {n}^{5}$

$\frac{36 {m}^{5} {n}^{5} }{12 {m}^{3} } = 3 {m}^{2} {n}^{5}$

5 0

3 years ago

Read 2 more answers

There's got to be someone who can answer this

Sphinxa [80]

Yes based on ja 82 and it can be added

4 0

3 years ago