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SSSSS [86.1K]
3 years ago
10

PLEASE HELP THANK YOU IN ADVANCE NEED TO SUBMIT SOON!! PLEASE PLEASE PLEASE HELP

Mathematics
1 answer:
Serjik [45]3 years ago
6 0
Provate school in 2005
f(t)=85+18t

public school
g(t)=95+15t

graph
easy
replace g(t) and f(t) with y
y=18t+85
y=15t+95
input values for t and get values for y

y=18t+85
when t=0 y=85
when t=1 y=103
plot the oints (0,85) and (1,103)

y=15t+95
if t=0 then y=95
if t=1 then y=110
plot the points (0,95) and (1,110)

the easier way would just to be to solve the equatons but anyway
interscection point is (3 and 1/3,145)

so after 3 years (2008) it is about 145
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2 years ago
In AGHI, h = 300 inches, G=30° and H=29º. Find the length of i, to the nearest<br> inch.
dalvyx [7]

Given:

In triangle GHI, h = 300 inches, G=30° and H=29º.

To find:

The length of i.

Solution:

We have, G=30° and H=29º.

Using angle sum property, we get

m\angle G+m\angle H+m\angle I=180^\circ

30^\circ+29^\circ+m\angle I=180^\circ

59^\circ+m\angle I=180^\circ

m\angle I=180^\circ-59^\circ

m\angle I=121^\circ

According to Law of sines,

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Using Law of sines, we get

\dfrac{h}{\sin H}=\dfrac{i}{\sin I}

\dfrac{300}{\sin 29^\circ}=\dfrac{i}{\sin 121^\circ}

\dfrac{300}{0.4848}=\dfrac{i}{0.8572}

Multiply both sides by 0.8572.

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i\approx 530

Therefore, the length of i is about 530 inches.

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3 years ago
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