Question

What is the solution to √3x+54 + 6 = 10

Answer 1

For this case we must solve the following equation:

$\sqrt {3x + 54} + 6 = 10$

Subtracting 6 from both sides of the equation:

$\sqrt {3x + 54} = 10-6\\\sqrt {3x + 54} = 4$

We square both sides of the equation squared:

$3x + 54 = 4 ^ 2\\3x + 54 = 16$

We subtract 54 from both sides of the equation:

$3x = 16-54$

Different signs are subtracted and the sign of the major is placed:

$3x = -38$

We divide between 3 on both sides:

$x = \frac {-38} {3}\\x = - \frac {38} {3}$

Answer:

$x = - \frac {38} {3}$

Answer 2

Answer:

x = -(38/3)

Step-by-step explanation:

Well first you have to isolate the square root on the left hand side.

Then eliminate the radical on the left hand side.

Last step

Solve the linear equation :

Rearranged equation

3x + 38 = 0

Subtract 38 from both sides

3x = -38

Divide both sides by 3

A possible solution is :

x = -(38/3)