The answer is (22) hope it helps have a great day
<em>PQR with vertices P(–2, 9), Q(7, –3), and R(–2, –3)</em>
<em>first distance P(–2, 9), Q(7, –3) </em>
<em>The distance (d) between two points is given by the following formula: </em>
<em>Answer= 15</em>
So you have to simplify
(9 x 10 x 18) 2 + (5 x 10 x 18) (-7) + (5 x 9 x 18)
(-11) + (5 x 9 x 10)
5 x 9 x 10 x 18
1620 x 2 + 900 (-7) + 810(-11) + 450 x 5
x 5 x 9 x 10 x 18
The answer would be -6/5
The point such that the coordinate is 5;3 is (14, 0)
<h3>Midpoint of coordinates using ratio</h3>
The formula for finding the midpoint of a line in the ratio m:n is expressed as:
M(x, y) = {(mx₁+nx₂)/2, (my₁+ny₂)/2,}
Given the coordinate of G and D on the line as G(5, 0) and D(1,0)
Since there is no y-axis, hence;
x = 5(5)+1(3)/2
x = 25+3/2
x = 28/2
x =14
Hence the point such that the ratio is 5;3 is (14, 0)
Learn more on midpoint of a line here: brainly.com/question/5566419
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Answer:X=110/121
Step-by-step explanation:
Multiply 100 by 1.21 then by x
121x=110
Divide both side by 121
X=110/121
X=0.91