Answer:

Step-by-step explanation:

Hello!
if x = -3, just substitute it for x (replace the x with -3)
2(-3) + 6 = 0
2 * -3 = -6
-6 + 6 = 0
I hope this helps, and have a nice day!
Answer:
H is the reflection of itself in the horizontal line
Answer:
r≥0
V(r) ≥0
Step-by-step explanation:
V(r) = 4/3 * Pi* r^3
The domain is the input values for r
The radius cannot be less than 0 but can be any number bigger than 0
What is the domain of the function in this situation?
r≥0
The range is the output values for the function or the volume
The volume must be greater than or equal to zero
V(r) ≥0