SHOW STEP BY STEP!!! I"LL MAKE YOU BRAINLEST AND if YOU COPY SOMEONE IM REPORTING YOU
2 answers:
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A thumb-wrestling match requires two thumbs, so we can either suppose that we need at least two people 
, or allow one to thumb-wrestle one's self. In either case, we'd have 
, so let's just say we need a minimum of two players.
If we add one more person to the set of players, then the first two people would need to play 1 additional match each. So
.
If we add one more person, then the first three people would again each have to play 1 more match with the new person. So
.
And so on, so that in general, the number of games needed for everyone to play exactly one match with everyone else is given recursively by
If we add one more person to the set of players, then the first two people would need to play 1 additional match each. So
If we add one more person, then the first three people would again each have to play 1 more match with the new person. So
And so on, so that in general, the number of games needed for everyone to play exactly one match with everyone else is given recursively by
Answer:
For this case we know that the confidence level is 90% so then the significance level is and
. And we can find in the normal standard distribution a value who accumulates 0.5 of the area on each tail and we got:
And the best option would be:
1.645
Step-by-step explanation:
We assume that the parameter of interest is and we can assume that the distribution for this parameter is normally distributed so then the confidence interval assuming a two sided interval is given by:
Where represent the estimator for the parameter, SE the standard error and
the critical value.
For this case we know that the confidence level is 90% so then the significance level is and
. And we can find in the normal standard distribution a value who accumulates 0.5 of the area on each tail and we got:
And the best option would be:
1.645