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4 years ago

What is the difference between AuB and AnB in a venn diagram??

Mathematics

1 answer:

Arte-miy333 [17]4 years ago

7 0

A∪B includes both of the two venn diagrams entirely.
A∩B includes only the intersection of the two venn diagrams.

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Medians $\overline{dp}$ and $\overline{eq}$ of $\triangle def$ are perpendicular. if $dp= 18$ and $eq = 24$, then what is ${de}$

monitta

Denote by M the point of intersection of the medians.
Denote also the distance DM by x and the distance QM by y.
From the median properties of triangles we know that
$y=\frac{1}{3}\timesFQ=\frac{1}{3}\times24=8$
Also,
$x=\frac{2}{3}\times DP=\frac{2}{3}\times 18=12$
Since the medians are perpendicular, we deduce that:
$x^2+y^2=DQ^2\iff DQ=\sqrt{8^2+12^2}=14.4$
Then, since $DE=2\times DQ\text{ then }DE=2\times 14.4=28.8$

6 0

4 years ago

Read 2 more answers

How many solutions are there for the pair of equations for lines Q and S? Explain your answer.

krek1111 [17]

No solution because the lines are parallel.

7 0

3 years ago

Read 2 more answers

Some parts of California are particularly earthquake-prone. Suppose that in one metropolitan area, 32% of all homeowners are ins

Bumek [7]

Answer:

$P(X = 0) = 0.2138$

$P(X = 1) = 0.4025$

$P(X = 2) = 0.2841$

$P(X = 3) = 0.0891$

$P(X = 4) = 0.0105$

Step-by-step explanation:

For each homeowner, there are only two possible outcomes. Either they have invested in earthquake insurance, or they have not. The probability of a home owner having invested in earthquake insurance is independent from other homeowners. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

32% of all homeowners are insured against earthquake damage.

This means that $p = 0.32$

Four homeowners are to be selected at random.

This means that $n = 4$

Find the probability distribution of X.

This is the probability of each outcome

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{4,0}.(0.32)^{0}.(0.68)^{4} = 0.2138$

$P(X = 1) = C_{4,1}.(0.32)^{1}.(0.68)^{3} = 0.4025$

$P(X = 2) = C_{4,2}.(0.32)^{2}.(0.68)^{2} = 0.2841$

$P(X = 3) = C_{4,3}.(0.32)^{3}.(0.68)^{1} = 0.0891$

$P(X = 4) = C_{4,4}.(0.32)^{4}.(0.68)^{0} = 0.0105$

6 0

3 years ago

The 2nd term in a geometic sequence is 20. the fourth term in the same sequence is 45/4 or 11.25. what is the common ratio in th

Over [174]

Let x be the value of the third term.
Since it's a geometric sequence, then:
Third term/Second term = Fourth term/Third term
x/20 = 11.25/x
Cross multiplication:
x^2 = 225
x = 15
So since the ratio is constant, then it is
x/20 = 15/20 = 3/4
So the common ratio is 3/4 or 0.75.

8 0

3 years ago

Express the function F in the form f ∘ g. (Enter your answers as a comma-separated list. Use non-identity functions for f(x) and

damaskus [11]

Answer:

$F(x) = f \circ g$