CAN SOMEONE HELP ME WITH THIS PROBLEM URGENT 5 STAR RATING AND BRAINLY IF SOLVED!

Is the least number to be added to 5607 to get a perfect square. pls add the steps.

daser333 [38]

Answer:

18

Step-by-step explanation:

70^2 = 4900 < 5607 < 6400 = 80^2

so sqrt(5607) is a two-digit number with tenth-digit 7

71^2 = 5041, 72^2 = 5184, 73^2 = 5329, 74^2 = 5476, 75^2 = 5625

so the smallest square bigger than 5607 is 75^2, which is 5625

so the number should ne 5625 - 5607 = 18

8 0

2 years ago

Find the 60th term of the arithmetic sequence −29,−49,−69,...

andreev551 [17]

Answer:

89

Step-by-step explanation:

it is basically counting by 2s but rather by 20s.

20, 40,60,80

all you do is add a 9 at the end.

6 0

3 years ago

Point p was rotated about the origin (0,0) by -15 degrees. Which point is the image of P?

Airida [17]

Answer:

the answer is d.

Step-by-step explanation:

8 0

3 years ago

Stewart wants to save for retirement and also pay off his mortgage. Each year, he has an extra $5,000. Should he put that extra

Evgesh-ka [11]

A) Yes, The tax benefits of Homeonership are similar to IRA tax breaks..!

Im not sure about my answer ..

hope it will help you dear ♡

7 0

3 years ago

Again ... Commute times in the U.S. are heavily skewed to the right. We select a random sample of 500 people from the 2000 U.S.

VladimirAG [237]

Answer:

We conclude that the mean commute time in the U.S. is less than half an hour.

Step-by-step explanation:

We are given that a random sample of 500 people from the 2000 U.S. Census is selected who reported a non-zero commute time.

In this sample the mean commute time is 27.6 minutes with a standard deviation of 19.6 minutes.

Let $\mu$ = mean commute time in the U.S..

So, Null Hypothesis, $H_0$ : $\mu \geq$ 30 minutes {means that the mean commute time in the U.S. is more than or equal to half an hour}

Alternate Hypothesis, $H_A$ : $\mu$ < 30 minutes {means that the mean commute time in the U.S. is less than half an hour}

The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean commute time = 27.6 minutes

s = sample standard deviation = 19.6 minutes

n = sample of people from the 2000 U.S. Census = 500

So, the test statistics = $\frac{27.6 -30}{\frac{19.6}{\sqrt{500} } }$ ~ $t_4_9_9$

= -2.738

The value of t test statistic is -2.738.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the t table gives critical values of -1.645 at 499 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of t as -2.378 < -1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean commute time in the U.S. is less than half an hour.

4 0

3 years ago