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mixas84 [53]
3 years ago
15

We invested $10000 into two bank accounts. One account earns 14% per year, the other account earns 8% per year. How much did we

invest into each account if after the first year, the combined interest from the two accounts is $1238?
Mathematics
1 answer:
Blababa [14]3 years ago
3 0

Answer:

$7,300 was invested in the 14% account while $2,700 was invested in the 8% interest account

Step-by-step explanation:

Let the amount invested in first account be $x while the amount for second account is $y

Mathematically;

x + y = 10,000 •••••••••(i)

Interest on first account

= 14% of x = 14/100 * x

Interest on second account

= 8% of y= 8/100 * y

Adding all together will give total

14/100 * x + 8/100 * y = 1238

Multiply through by 100

14x + 8y = 123800 •••••••(ii)

From equation 1, x = 10,000 - y

Insert this into second equation

14(10,000-y) + 8y = 123,800

140,000 - 14y + 8y = 123,800

140,000 - 6y = 123,800

6y = 140,000 - 123,800

6y = 16,200

y = 16,200/6

y = $2,700

Recall

x + y = 10,000

x = 10000 - y

x = 10,000 - 2,700

x = $7,300

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So looking at this from my bed, as a bored 11 year old, 2,910 is the rounded version of 2,912. Not to make you do work or anything but 2,910 divided by 95!
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Digiron [165]

Answer:

wouldn't be $30 all together

Step-by-step explanation:

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3 years ago
It’s a new semester!students are grouped into three clubs, which each has 10,4 and 5 students.In how many ways can teacher sleep
My name is Ann [436]

The total number of ways to select 2 students from the 3 clubs is 55 ways.

Since there are three clubs which each has 10, 4 and 5 students, and we require the number of ways a teacher can select 2 students so that they are from different clubs.

Since order doesn't matter and anybody can be chosen first, we use combination theory.

<h3 /><h3>Number of ways of selecting from the first two clubs</h3>

Since we have two slots, to select the first person from the first club, we ¹⁰C₁. For the second student from the club of 4, we have ⁴C₁. Also, there are 2 ways of selecting the two students.

So, there are ¹⁰C₁ × ⁴C₁/2!

= 10 × 4/2

= 20 ways from the first two clubs.

<h3 /><h3>Number of ways of selecting from the next two clubs</h3>

For the next two clubs of 4 and 5 students, for the first slot, we have ⁴C₁. For the second student, we have ⁵C₁. Also, there are 2 ways of selecting the two students.

So, there are ⁴C₁ × ⁵C₁/2!

= 4 × 5/2

= 10 ways from the next two clubs.

<h3 /><h3>Number of ways of selecting from the last two clubs</h3>

For the first and last club of 10 and 5 students, for the first slot, we have ¹⁰C₁. For the second student, we have ⁵C₁.  Also, there are 2 ways of selecting the two students.

So, there are ¹⁰P₁ × ⁵P₁/2!

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<h3 /><h3>Total number of ways of selecting two students from the 3 clubs.</h3>

So, the total number of ways to select 2 students from the 3 clubs is 20 + 10 + 25 = 55 ways.

So, the total number of ways to select 2 students from the 3 clubs is 55 ways.

Learn more about combinations here:

brainly.com/question/25990169

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Answer:

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sladkih [1.3K]

Answer: 8 hours

<u>Step-by-step explanation:</u>

Company 1: 3.25x + 26

Company 2: 3.50x + 24


3.50x + 24 = 3.25x + 26

0.25x  +24 = 26        <em>subtracted 3.25x from both sides</em>

0.25x = 2            <em>subtracted 24 from both sides</em>

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<u>Check:</u>

Company 1: 3.25x + 26  =  3.25(8) + 26  = $52

Company 2: 3.50x + 24  = 3.50(8) + 24  = $52

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