Answer:
C) (1, 12)
Step-by-step explanation:
You can rewrite the equation in vertex form:
y = -4(x^2 -2x) +8 . . . . . factor the leading coefficient from the first two terms
y = -4(x^2 -2x +1) +8 +4 . . . . . add the square of half the x-coefficient inside parentheses (-4)((-2/2)^2) and its opposite outside parentheses (-(-4)).
Now, the equation can be written in vertex form.
y = a(x -h)^2 +k . . . . . . . . . has vertex (h, k)
y = -4(x -1)^2 +12 . . . . . . . . has vertex (1, 12)
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<em>Comment on the problem</em>
The typewritten form of the equation seems to have a missing leading minus sign. Its vertex is (-1, 4), so "none of the above."
The similarities are they are all quadrilaterals. the differences are a rectangle has two different sets of equal side, a square sides are all right angles all the same size, and a rhombus has opposite equal acute angles.
Answer:
Step-by-step explanation:
- 8x + 44 ≥ 60
Subtract 44 from both sides
- 8x + 44 - 44 ≥ 60 - 44
- 8x ≥ 16
Divide both sides by -8 and flip the inequality sign
-8x/-8 ≤ 16/-8
x ≤ -2
x = { ......... -4,-3,-2}
2) -4x + 50 < 58
Subtract 50from both sides
-4x + 50 -50 < 58- 50
-4x < 8
Divide both sides by -4 and flip the inequality sign
-4x/-4 > 8/-4
x > -2
x= {-1, 0 , 1 , 2....... }
Answer:
Step-by-step explanation: