So... we have two numbers
say "a" and "b"
one is larger than the other, let us say, "b" is larger than "a"
by how much?
well, "<span>eight more than three times"
three times the smaller is 3 * a, or 3a
eight more than that is 3a + 8
so b = 3a+ 8
the sum of both of them is 52
so, we know that
a + b = 52
run a substitution on "b" on the 2nd equation, and solve for "a"
once you find "a", plug it back in the 2nd equation, to get "b"
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Answer:
Step-by-step explanation:
Answer:
x=−
1.6875
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Answer:
11) A
12) B
13) C
14) D
Step-by-step explanation:
11) 4 times left, 1 up
12) 4 times right, 4 up
13) 1 time left, 1 down
14) 2 times left, 2 up
Answer:
<em>Their masses are 100 kg and 90 kg</em>
Step-by-step explanation:
<u>Equations</u>
We'll solve the problem by setting only one variable. Let's call:
x = weight of the heavier boxer
Since the sum of the masses of both boxers is 190 Kg:
190 - x = mass of the lighter boxer.
It's given that 
of the mass of the heavier boxer is 10 kg less than the mass of the other, thus:
Operating:
Multiplying by 5:
Simplifying:
The heavier boxer's mass is 100 kg. The lighter boxer has a mass of 190-100 = 90 kg.
Their masses are 100 kg and 90 kg
