Step-by-step explanation:
Your problem → 5y+5/2 / 25y-20/40y^2-32y
5y+5/2÷25y-20/40y^2-32y
=5⋅y+5/2÷25×y-20/40×y^2-32×y
=5y+5/2÷25×y-20/40×y^2-32y
=5y+5/2×1/25×y-20/40×y^2-32y
=5y+y/10-20/40×y^2-32y
=5y+y/10-y^2/2-32y
=5y×10+y-y^2×5-32y×10 ÷ 10
=50y+y-5y2-320y ÷ 10
= -269y-5y^2 / 10
2 sides could be 0.4 and 2 sides could be 0.3 :)
Answer:
5.1
Step-by-step explanation:
14^-2*1000
The answer to your question is... 68
/ \
32(times)2
/ \
17(times)2
Answer:
Simple random should be the technique used
