Coal seams are far deep underground to be considered for opencast minings. These coal seams require underground mining. Since it is too deep underground, it can be used for mapping and correlation of sedimentary rocks or as a key bed.
Answer:
C
Explanation:
Homologous structures compare the same anatomical features in different species. C is correct because it compares the same trait (wings) in different species (dragonfly vs. bat)
TAG CCT ATG - Template Strand
AUC GGA UAG - mRNA Strand
from this you can find out which amino acids are which.
There's an excess of Phosphorus in soil, the plants consume it, then the primary consumers consume multiple plants, and have a higher level of phosphorus concentration in them. Then secondary consumers consume multiple primary consumers and the phosphorus from all the things they ate are concentrated in them, and so on. Basically, even though as energy is passed along the food chain, it lessens with each trophic level, nutrients become more concentrated and the highest trophic level has the highest concentration because of how many organisms were consumed.
Answer:
We have two alleles, XA and Xa and the genotypic frequencies are given by p^2 + 2pq + q^2 = 1
In this equation XA is p and Xa is q. Therefore p^2 is the frequency of the genotype XAXA, etc.
For X-linked conditions, females have 2 alleles for the gene, but males only have one. So calculate the genotypic frequencies for males and females separately. Since the population is in Hardy-Weinberg equilibruim, the allelic frequency is the same for both sexes.
Since males only have one X chromosome, the frequency of X linked in male is equal to the allelic frequency. So frequency just equals 1/5000 or 0.0002
so q^2 = q for males in X linked
So q = 0.0002
for females, she would need to have both alleles, so her frequency of the homozygous genotype is q^2 = 0.0002^2 = 0.00000004
number of affected females would be q^2 x number of females in the population
so 0.00000004 x 160 mil = 6.4 females would have hemophilia.
Explanation: