Answer:
<em>Part A: 3,</em>
<em>Part B: - 4</em>
Step-by-step explanation:
<em>~ Part A ~ </em>
The problem would be in terms of such an expression: ( - 6 - ( - 3 )^2 )/ -5
Now knowing the expression, let us simplify in terms of basic algebra:
( -6 - 9 )/ -5 = ( - 15/ - 5 ) = <em>Answer; 3</em>
<em>~ Part B ~ </em>
We know the problem to be p^2/ r, but we must substitute the value of p being -10, and r ⇒ -25: ( - 10 )^2/ -25
Now let us simplify the expressions:
( - 10 )^2/ -25 = 100/ - 25 =<em> Answer; -4</em>
Answer:
150 CASH
Step-by-step explanation:
if you do 25 down and 12 dollar for 11 month you pay 7 more dollars
Answer:
The first set of consecutive even integers equals (8 , 6)
The second set is ( - 8 and - 6) which also works.
Step-by-step explanation:
Equation
(x)^2 + (x + 2)^2 = (x)(x + 2) + 52 Remove the brackets on both sides
Solution
x^2 + x^2 + 4x + 4 = x^2 + 2x + 52 Collect the like terms on the left
2x^2+ 4x+ 4 = x^2 + 2x + 52 Subtract right side from left
2x^2 - x^2 + 4x - 2x + 4 - 52 = 0 Collect the like terms
x^2 + 2x - 48 = 0 Factor
(x + 8)(x - 6) = 0
Answer
Try the one you know works.
x - 6 = 0
x = 6
Therefore the two integers are 6 and 8
6^2 + 8^2 = 100
6*8 + 52 = 100
So 6 and 8 is one set of consecutive even numbers that works.
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What about the other set.
x + 8 = 0
x = - 8
x and x + 2
- 8 and -8 + 2 = - 8, - 6
(- 8 )^2 + (- 6)^2 = 100
(-8)(-6) + 52 = 100
Both sets of consecutive numbers work.
X^2+9x+24=0 i believe, i’m only in 7th grade so
also, you factor the equation equal to zero and factor the left side
