Your answer is below (for y)
y=−23x+950
Your answer for x is
x=−y/23+950/23x
Answer:
3/1
Step-by-step explanation:
You would count how far up it goes, with out it passing the dot (also know as the rise) which in this case is 3. Then you would count the number of space to go to the side (the run) so in this case it would be 1. Finally you would put rise over run and get 3/1.
<h3>
Answer: E) 1/5</h3>
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Method 1
Use your calculator to find the decimal version of each fraction
- 4/10 = 0.40
- 12/25 = 0.48
- 14/20 = 0.70
- 28/50 = 0.56
- 1/5 = 0.20
We see that 0.20 is the smallest decimal of the list, so 1/5 is the smallest fraction of the list.
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Method 2
To compare fractions, we need to get all of the denominators to the same value. A good target is the lowest common denominator (LCD)
In this case, the LCD is 100
- 4/10 = 40/100 .... multiply top and bottom by 10
- 12/25 = 48/100 .... multiply top and bottom by 4
- 14/20 = 70/100 .... multiply top and bottom by 5
- 28/50 = 56/100 .... multiply top and bottom by 2
- 1/5 = 20/100 .... multiply top and bottom by 20
The last fraction has the smallest denominator, so 1/5 is the smallest.
Answer:
![\[3x+\frac{2}{3}\]](https://tex.z-dn.net/?f=%5C%5B3x%2B%5Cfrac%7B2%7D%7B3%7D%5C%5D)
Step-by-step explanation:
![\[f(x)=x-\frac{1}{3}\]](https://tex.z-dn.net/?f=%5C%5Bf%28x%29%3Dx-%5Cfrac%7B1%7D%7B3%7D%5C%5D)
![\[g(x)=3x+1\]](https://tex.z-dn.net/?f=%5C%5Bg%28x%29%3D3x%2B1%5C%5D)
Hence, ![\[(f o g)(x)=f(3x+1)\]](https://tex.z-dn.net/?f=%5C%5B%28f%20o%20g%29%28x%29%3Df%283x%2B1%29%5C%5D)
But, ![\[f(3x+1)=(3x+1)-\frac{1}{3}\]](https://tex.z-dn.net/?f=%5C%5Bf%283x%2B1%29%3D%283x%2B1%29-%5Cfrac%7B1%7D%7B3%7D%5C%5D)
Simplifying,
![\[f(3x+1)=3x+(1-\frac{1}{3})\]](https://tex.z-dn.net/?f=%5C%5Bf%283x%2B1%29%3D3x%2B%281-%5Cfrac%7B1%7D%7B3%7D%29%5C%5D)
= ![\[f(3x+1)=3x+(\frac{3-1}{3})\]](https://tex.z-dn.net/?f=%5C%5Bf%283x%2B1%29%3D3x%2B%28%5Cfrac%7B3-1%7D%7B3%7D%29%5C%5D)
= ![\[f(3x+1)=3x+(\frac{2}{3})\]](https://tex.z-dn.net/?f=%5C%5Bf%283x%2B1%29%3D3x%2B%28%5Cfrac%7B2%7D%7B3%7D%29%5C%5D)
Hence, ![\[(f o g)(x)=3x+(\frac{2}{3})\]](https://tex.z-dn.net/?f=%5C%5B%28f%20o%20g%29%28x%29%3D3x%2B%28%5Cfrac%7B2%7D%7B3%7D%29%5C%5D)
