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Marrrta [24]
3 years ago
6

help please Steps to Completing This Discussion Based Assessment: Complete ONE problem from each of the 6 parts on the assignmen

t attached below. You need to show work for each of the 6 problems you choose to do.
Mathematics
2 answers:
kotegsom [21]3 years ago
8 0

Answer:

Part A number 2 (see work below)

<em>*please give me brainliest lol*</em>

Step-by-step explanation:

(8r^3 + 2r^2 + 1) - (7 - 7r^3 + 3r^2)

<em>after factoring out the negative, you'll have:</em>

8r^3 + 2r^2 + 1    -7 + 7r^3 - 3r^2

<em>now we combine like terms, and your answer is:</em>

15r^3 - r^2 - 6

<u>hope this helps!</u>

Anastaziya [24]3 years ago
7 0

Answer:

<em>See solution( s ) below</em>

Step-by-step explanation:

1.

( 2r + 4r^2 - 4r^3 ) - ( 5r^2 - 7r + 3r^3 ) ,\\2r+4r^2-4r^3-\left(5r^2-7r+3r^3\right),\\2r+4r^2-4r^3-5r^2+7r-3r^3,\\\\Simplified, -7r^3-r^2+9r

To solve this problem, I distributed the negative to the values in ( ), and grouped like elements!

2.

( 8x + 8 )( 8v^2 + 4x - 8 ),\\8x\cdot \:8v^2+8x\cdot \:4x+8x\left(-8\right)+8\cdot \:8v^2+8\cdot \:4x+8\left(-8\right),\\\\Simplified, 32x^2+64v^2x-32x+64v^2-64

Expanding the values in ( ), I combined like terms once more, and simplified the expression!

3.

54b^7+81b^6 + 72b^4,\\Greatest Common Factor = 9b^4\\Factored, 9b^4\left(6b^3+9b^2+8\right)

4.

16p^3 +12p^2 + 12p + 9,\\\left(16p^3+12p^2\right)+\left(12p+9\right),\\3\left(4p+3\right)+4p^2\left(4p+3\right),\\\\Factored, \left(4p+3\right)\left(4p^2+3\right)

5.

x^2 + 8x - 20,\\( x^2 - 2x ) + ( 10x - 20 ),\\x * ( x - 2 ) + 10 * ( x - 2 ),\\\\Factored, ( x - 2 )( x + 10 )

6.

2\sqrt{ 45 } - \sqrt{ 20 }\\6\sqrt{ 5 } - 2\sqrt{ 5 },\\\\Solution, 4\sqrt{ 5 }

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ziro4ka [17]
The answer is x=7
Hope this helps

3 0
3 years ago
Find the following algebra, I am in class and plz give explanation
Lelechka [254]

1) Solving 4a+4b-ac-bc we get (a+b)(4-c)

2) Solving 16a^4-8b we get 8(2a^4-b)

3) Solving x^2-8x+15 we get (x-3)(x-5)

Step-by-step explanation:

We need to solve the following expressions:

1) 4a+4b-ac-bc

We will solve this expression by factoring common terms:

4a+4b-ac-bc

Factoring 4 from 4a+4b and -c from -ac-bc

4(a+b)-c(a+b)

Taking common term

(a+b)(4-c)

2) 16a^4-8b

We will solve this expression by factoring common terms:

16a^4-8b

Taking 8 as common term:

8(2a^4-b)

3) x^2-8x+15

We can solve the expression by breaking the middle term into 2

x^2-3x-5x+15\\Finding\,\,common:\\=x(x-3)-5(x-3)\\=(x-3)(x-5)

Keywords: Finding factors

Learn more about Finding factors at:

  • brainly.com/question/10771256
  • brainly.com/question/1332667
  • brainly.com/question/1357167

#learnwithBrainly

6 0
3 years ago
Help help help plz help answer this questioonnnn
Llana [10]

Answer:

D

Step-by-step explanation:

goodluck!

7 0
3 years ago
Read 2 more answers
How to do question five
-BARSIC- [3]
I believe the answer is 46.
Remember "PEMDAS" when doing equations like these :)
8 0
3 years ago
A rectangle has a length of (x+5)and a with of x Write down the expression for the area of a rectangle If the area is 24cm²,find
ratelena [41]

Answer: Width = 3cm

Length = 8cm

Step-by-step explanation:

Length = x+5 cm

Width = xcm

Area = 24cm²

Area of a rectangle = length × width

x × (x + 5) = 24

x² + 5x = 24

x² + 5x - 24 = 0

x² + 8x - 3x - 24 = 0

x(x + 8) - 3(x + 8) = 0

x - 3 = 0

x = 3

Width = 3cm

Since length = x + 5 = 3 + 5 = 8cm

Length = 8cm

8 0
3 years ago
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