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Marrrta [24]
3 years ago
6

help please Steps to Completing This Discussion Based Assessment: Complete ONE problem from each of the 6 parts on the assignmen

t attached below. You need to show work for each of the 6 problems you choose to do.
Mathematics
2 answers:
kotegsom [21]3 years ago
8 0

Answer:

Part A number 2 (see work below)

<em>*please give me brainliest lol*</em>

Step-by-step explanation:

(8r^3 + 2r^2 + 1) - (7 - 7r^3 + 3r^2)

<em>after factoring out the negative, you'll have:</em>

8r^3 + 2r^2 + 1    -7 + 7r^3 - 3r^2

<em>now we combine like terms, and your answer is:</em>

15r^3 - r^2 - 6

<u>hope this helps!</u>

Anastaziya [24]3 years ago
7 0

Answer:

<em>See solution( s ) below</em>

Step-by-step explanation:

1.

( 2r + 4r^2 - 4r^3 ) - ( 5r^2 - 7r + 3r^3 ) ,\\2r+4r^2-4r^3-\left(5r^2-7r+3r^3\right),\\2r+4r^2-4r^3-5r^2+7r-3r^3,\\\\Simplified, -7r^3-r^2+9r

To solve this problem, I distributed the negative to the values in ( ), and grouped like elements!

2.

( 8x + 8 )( 8v^2 + 4x - 8 ),\\8x\cdot \:8v^2+8x\cdot \:4x+8x\left(-8\right)+8\cdot \:8v^2+8\cdot \:4x+8\left(-8\right),\\\\Simplified, 32x^2+64v^2x-32x+64v^2-64

Expanding the values in ( ), I combined like terms once more, and simplified the expression!

3.

54b^7+81b^6 + 72b^4,\\Greatest Common Factor = 9b^4\\Factored, 9b^4\left(6b^3+9b^2+8\right)

4.

16p^3 +12p^2 + 12p + 9,\\\left(16p^3+12p^2\right)+\left(12p+9\right),\\3\left(4p+3\right)+4p^2\left(4p+3\right),\\\\Factored, \left(4p+3\right)\left(4p^2+3\right)

5.

x^2 + 8x - 20,\\( x^2 - 2x ) + ( 10x - 20 ),\\x * ( x - 2 ) + 10 * ( x - 2 ),\\\\Factored, ( x - 2 )( x + 10 )

6.

2\sqrt{ 45 } - \sqrt{ 20 }\\6\sqrt{ 5 } - 2\sqrt{ 5 },\\\\Solution, 4\sqrt{ 5 }

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Answer:

x = 6/31 = 0.194

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    (62)-(12/x)=0

Step by step solution :

Step  1  :

           12

Simplify   ——

           x

Equation at the end of step  1  :

       12

 62 -  ——  = 0

       x

Step  2  :

Rewriting the whole as an Equivalent Fraction :

2.1   Subtracting a fraction from a whole

Rewrite the whole as a fraction using  x  as the denominator :

          62     62 • x

    62 =  ——  =  ——————

          1        x  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

62 • x - (12)     62x - 12

—————————————  =  ————————

      x              x    

Step  3  :

Pulling out like terms :

3.1     Pull out like factors :

  62x - 12  =   2 • (31x - 6)

Equation at the end of step  3  :

 2 • (31x - 6)

 —————————————  = 0

       x      

Step  4  :

When a fraction equals zero :

4.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 2•(31x-6)

 ————————— • x = 0 • x

     x    

Now, on the left hand side, the  x  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  2  •  (31x-6)  = 0

Equations which are never true :

4.2      Solve :    2   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

4.3      Solve  :    31x-6 = 0

Add  6  to both sides of the equation :

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Answer :

                  x = 6/31 = 0.194

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\qquad \qquad  \bf \huge\star \:  \:  \large{  \underline{Answer} }  \huge \:  \: \star

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\textsf{  \underline{\underline{Steps to solve the problem} }:}

\qquad❖ \:  \sf \:2x + 6 + 5x + 90 = 180

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\qquad❖ \:  \sf \:7x + 6 = 90

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\qquad \large \sf {Conclusion}  :

\qquad❖ \:  \sf \:x = 12 \degree

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