let's use some amount.... hmmm say "b", to get its percentage.
![\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{140\% of b}}{\left( \cfrac{140}{100} \right)b}\implies \cfrac{14}{10}b\implies \cfrac{7}{5}b\implies 1\frac{2}{5}b](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Ba%5C%25%20of%20b%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20%5Cleft%28%20%5Ccfrac%7Ba%7D%7B100%7D%20%5Cright%29%5Ccdot%20b%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D~%5Chspace%7B5em%7D%5Cstackrel%7B%5Ctextit%7B140%5C%25%20of%20b%7D%7D%7B%5Cleft%28%20%5Ccfrac%7B140%7D%7B100%7D%20%5Cright%29b%7D%5Cimplies%20%5Ccfrac%7B14%7D%7B10%7Db%5Cimplies%20%5Ccfrac%7B7%7D%7B5%7Db%5Cimplies%201%5Cfrac%7B2%7D%7B5%7Db)
Answer by JKismyhusbandbae: Bowler 2 as well has a higher maximum score. While Bowler 1 is less by almost 20 points.
Answer:
c. y = -x +2
Step-by-step explanation:
pass (0,2): y interception = 2
Line: y=mx+b b=2
Okay, so first you draw a picture and let x be the distance from point D to the rest stop. Then the distance from point to the rest stop is 8 - x
You know that the length of the new trail is y + z, where y is the distance from Ancaster to the rest stop and z is the distance from Dundas to the rest stop.
Now by the Pythagorean theorem, y^2 = 4^2 + x^2 and z^2 = 6^2 + (8 - x) ^2
So take square roots of these, add them, and minimize.
Note: I am assuming the path is perfectly straight, otherwise this approach fails.