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rjkz [21]
3 years ago
6

How do you do the problem a(b+c+1)

Mathematics
1 answer:
Harrizon [31]3 years ago
3 0
Use the distributive property, so do ab + ac + a(1) = ab + ac + a. Then substitute your values for a, b, and c to find the answer
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Write 1,200 in scientific notation
iVinArrow [24]

Answer: 1.2 10x ^3

Step-by-step explanation:

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3 years ago
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What is the coefficient of x2y3 in the expansion of (2x + y)5?
Zigmanuir [339]

Option C:

The coefficient of x^{2} y^{3} is 40.

Solution:

Given expression:

(2 x+y)^{5}

Using binomial theorem:

(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}

Here a=2 x, b=y

Substitute in the binomial formula, we get

(2x+y)^5=\sum_{i=0}^{5}\left(\begin{array}{l}5 \\i\end{array}\right)(2 x)^{(5-i)} y^{i}

Now to expand the summation, substitute i = 0, 1, 2, 3, 4 and 5.

$=\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}+\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1}+\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}+\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}

                                                            $+\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}+\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}

Let us solve the term one by one.

$\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}=32 x^{5}

$\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1} = 80 x^{4} y

$\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}= 80 x^{3} y^{2}

$\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}= 40 x^{2} y^{3}

$\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}= 10 x y^{4}

$\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}=y^{5}

Substitute these into the above expansion.

(2x+y)^5=32 x^{5}+80 x^{4} y+80 x^{3} y^{2}+40 x^{2} y^{3}+10 x y^{4}+y^{5}

The coefficient of x^{2} y^{3} is 40.

Option C is the correct answer.

5 0
3 years ago
The diagram shows circle C. Which of these statement is true?
Natali5045456 [20]

Answer:

the answer is b I know how to kill

6 0
2 years ago
Anyone know this? Ill give brainliest if right pls help ^^
Varvara68 [4.7K]

Answer:

Female=14 male=6

Step-by-step explanation:

Oof this toke long I understand it now, for yesterday you gotta do  6+6+6+6+6=30 this is the male and so you add 14 to 30=44, now comes the important part of solving this problem. For today you gotta add 4 men and 4 women so you do 6+6+6+6=24 now 14+14+14+14=56 and if you add 56+24=80 .

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3 years ago
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rjkz [21]

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Step-by-step explanation:

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