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Greeley [361]
3 years ago
8

Compute the probability that exactly 8 of the 20 internet browser users use chrome as their internet browser (to 4 decimals). fo

r this question, if you compute the probability manually, make sure to carry at least six decimal digits in your calculations.
Mathematics
1 answer:
dybincka [34]3 years ago
5 0

Answer:

2.4%

Step-by-step explanation:

We make use of the binomial probability equation, which is as follows:

P = [n! / (n - r)! r!] p ^ r * q ^ (n - r)

where,

n total number samples = 20

r is the selected number = 8

p, sin este valor no se puede realizar el ejercicio y no lo mencionas, pero encontré una pregunta igual y era de 20.37%, es decir 0.2037

q = 1 - 0.2037 = 0.7963

reemplazando:

P = [20! / ((20 - 8)! * 8!)] * [0.2037 ^ 8 * 0.7963 ^ (20 - 8)]

P = 125970 * 1.92685405*10^-7

P = 0.024 = 2.4%

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Answer:

7 IS LESS THAN OR EQUAL TO 7-.75X+1.29

Step-by-step explanation:

X IS THE NUMBER OF BAGELS BOUGHT

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Can someone help with this question? Thank u! :)
MatroZZZ [7]

Answer:

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Step-by-step explanation:

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3 years ago
Allied Corporation is trying to sell its new machines to Ajax. Allied claims that the machine will pay for itself since the time
kvasek [131]

Answer:

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

Step-by-step explanation:

We must evaluate the differences of the means of the two machines, to do so, we will assume a CI  of 95%, and as the interest is to find out if the new machine has better performance ( machine has a bigger efficiency or the new machine produces more units per unit of time than the old one) the test will be a one tail-test (to the left).

New machine

Sample mean                  x₁ =    25

Sample variance               s₁  = 27

Sample size                       n₁  = 45

Old machine

Sample mean                    x₂ =  23  

Sample variance               s₂  = 7,56

Sample size                       n₂  = 36

Test Hypothesis:

Null hypothesis                         H₀             x₂  -  x₁  = d = 0

Alternative hypothesis             Hₐ            x₂  -  x₁  <  0

CI = 90 %  ⇒  α =  10 %     α = 0,1      z(c) = - 1,28

To calculate z(s)

z(s)  =  ( x₂  -  x₁ ) / √s₁² / n₁  +  s₂² / n₂

s₁  = 27     ⇒    s₁²  =  729

n₁  = 45    ⇒   s₁² / n₁    = 16,2

s₂  = 7,56   ⇒    s₂²  = 57,15

n₂  = 36     ⇒    s₂² / n₂  =  1,5876

√s₁² / n₁  +  s₂² / n₂  =  √ 16,2  + 1.5876    = 4,2175

z(s) = (23 - 25 )/4,2175

z(s)  =  - 0,4742

Comparing z(s) and  z(c)

|z(s)| < | z(c)|  

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

The very hight dispersion of values s₁ = 27 is evidence of frecuent values quite far from the mean

3 0
3 years ago
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