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Greeley [361]
3 years ago
8

Compute the probability that exactly 8 of the 20 internet browser users use chrome as their internet browser (to 4 decimals). fo

r this question, if you compute the probability manually, make sure to carry at least six decimal digits in your calculations.
Mathematics
1 answer:
dybincka [34]3 years ago
5 0

Answer:

2.4%

Step-by-step explanation:

We make use of the binomial probability equation, which is as follows:

P = [n! / (n - r)! r!] p ^ r * q ^ (n - r)

where,

n total number samples = 20

r is the selected number = 8

p, sin este valor no se puede realizar el ejercicio y no lo mencionas, pero encontré una pregunta igual y era de 20.37%, es decir 0.2037

q = 1 - 0.2037 = 0.7963

reemplazando:

P = [20! / ((20 - 8)! * 8!)] * [0.2037 ^ 8 * 0.7963 ^ (20 - 8)]

P = 125970 * 1.92685405*10^-7

P = 0.024 = 2.4%

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belka [17]
Well, the area of a trapezoid is A = (b_{1} + b_{2}) * h * 1/2 so you can use the area of a parallelogram, which is A = l * w, by splitting the trapezoid into 2 triangles and one rectangle. So you'd use A = l * w for the rectangle and A = 1/2bh for the triangles. You'd get the same answer!
8 0
3 years ago
The points R(3,−3), S(8,0), and T(4,1) are connected to form △RST.
Lady bird [3.3K]

right isosceles

rs:34&rs=rt+st

rt:17

st:17

ab=[(x(a)-x(b))+(y(a)+y(b))]

5 0
3 years ago
Read 2 more answers
Can I get help on this question or an example? I would really appreciate it.
gulaghasi [49]

Answer:

B = 0.95m + 29.95

Step-by-step explanation:

this is really y = mx + b

m is a rate, 0.95 per mile

b is the y-intercept, or the price you pay no matter what, 29.95

8 0
3 years ago
Please help me with this question!
gavmur [86]
First off, let's convert the percentages to decimal format, so our 77% turns to 77/100 or 0.77, and our 55% turns to 55/100 or 0.55 and so on

now, the sum of both salines, must add up to the 77% mixture, let's say is "y"
so, 11 + 4 = y, and whatever the concentration level is, must also sum up to the mixture's concentration of 77%

anyway   thus

\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentrated\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{first sol'n}&11&x&11x\\
\textit{second sol'n}&4&0.55&2.20\\
------&-----&-------&-------\\
mixture&y&0.77&0.77y
\end{array}\\\\
-------------------------------\\\\
\begin{cases}
11+4=y\implies 15=\boxed{y}\\
11x+2.2=0.77y\\
----------\\
11x+2.2=0.77\cdot \boxed{15}
\end{cases}

solve for "x"
6 0
3 years ago
3)
Wewaii [24]

Answer:

For covering  1 unit area of the entire playground, the amount of sand required is equal to volume of 3 buckets of sand.

Step-by-step explanation:

Given -

\frac{1}{3} volume of sand in bucket is able to cover \frac{1}{9} area of the entire playground

Thus,

For covering  \frac{1}{9} unit area of the entire playground, the amount of sand required is equal to  \frac{1}{3}  of the total volume of sand in bucket

For covering  1 unit area of the entire playground, the amount of sand required is equal to

\frac{\frac{1}{3} }{\frac{1}{9} } \\\\\frac{1}{3}  * \frac{9}{1} \\\frac{9}{3}\\= 3

For covering  1 unit area of the entire playground, the amount of sand required is equal to volume of 3 buckets of sand.

4 0
3 years ago
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