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myrzilka [38]
3 years ago
11

Which of these is a unit rate. $3 for 3 hot dogs, $5 for a case of soda, $16 for 2 movie tickets, $8 for 6 cupcakes

Mathematics
2 answers:
blondinia [14]3 years ago
5 0
$5 for a case of soda
BlackZzzverrR [31]3 years ago
5 0
$5 for a case of soda
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Can yall like--- help????? i suck at geometry
SSSSS [86.1K]

Answer:

you do Length x Width x height

8  3/8 x 6 x 8  1/4 = 414.56

hope this helps :-)

7 0
3 years ago
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Kryger [21]

Answer:

1)

Given the triangle RST with Coordinates  R(2,1), S(2, -2) and T(-1 , -2).

A dilation is a transformation which produces an image that is the same shape as original one, but is different size.  

Since, the scale factor \frac{5}{3} is greater than 1, the image is enlargement or a stretch.  

Now, draw the dilation image of the triangle RST with center (2,-2) and scale factor \frac{5}{3}

Since, the center of dilation at S(2,-2) is not at the origin, so the point S and its image S{}' are same.

Now, the distances from the center of the dilation at point S to the other points R and T.  

The dilation image will be\frac{5}{3} of each of these distances,

SR=3, so S{}'R{}'=5 ;


ST=3, so S{}'T{}'=5  

Now, draw the image of RST i.e R'S'T'

Since, RT=3\sqrt{2} [By using hypotenuse of right angle triangle] and R{}'T{}'=5\sqrt{2}.


2)

(a)

Disagree with the given statement.

Side Angle Side postulate (SAS) states that:

If two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle then these two triangles are congruent.

Given: B is the midpoint of \overline{AC} i.e \overline{AB}\cong \overline{BC}

In the triangle ABD and triangle CBD, we have

\overline{AB}\cong \overline{BC}   (SIDE)            [Given]

\overline{BD}\cong \overline{BD}   (SIDE)            [Reflexive post]

Since, there is no included angle in these triangles.

∴ \Delta ABD is not congruent to \Delta CBD .

Therefore, these triangles does not follow the SAS congruence postulates.

(b)

SSS(SIDE-SIDE-SIDE) states that if three sides of one triangle are congruent to three sides of another triangle, then the triangles are congruent.

Since it is also given that  \overline{AD}\cong \overline{CD}.

therefore, in the triangle ABD and triangle CBD, we have

\overline{AB}\cong \overline{BC}   (SIDE)            [Given]

\overline{AD}\cong \overline{CD}   (SIDE)           [Given]

\overline{BD}\cong \overline{BD}   (SIDE)            [Reflexive post]

therefore by, SSS postulates \Delta ABD\cong \Delta CBD.

3)

Given that:  \angle1=\angle 3 are vertical angles, as they are formed by intersecting lines.

Therefore

, by the definition of linear pairs

\angle 1 and \angle 2 and \angle 3  and \angle 2 are linear pair.

By linear pair theorem, \angle 1 and \angle 2   are supplementary, \angle 2 and \angle 3  are supplementary.

m\angle1+m\angle 2=180^{\circ}

m\angle2+m\angle 3=180^{\circ}

Equate the above expressions:

m\angle 1+m\angle 2=m\angle 2+m\angle 3

Subtract the angle 2 from both sides in the above expressions

∴m\angle 1=m\angle 3

By Congruent Supplement theorem: If two angles are supplements of the same angle, then the two angles are congruent.


therefore, \angle 1\cong \angle 3.















3 0
3 years ago
Read 2 more answers
For a Brainlist !!!!!!!
UNO [17]

y=-7x+2

m=-7, so that's a negative slope.

b=2, so the y-intercept is (0,2).  That's a postiive y-intercept.

Solve 0=-7x+2 to find the x-intercept.

     7x=2

       x=2/7

The x-intercept is (2/7,0), so that's a positive x-intercept.

6 0
2 years ago
Please help meeeeeeeeee
aalyn [17]
C.) 1600 pi cm3

When you do 10^2 you get 100 and you multiply that by the height so 16 and you get 1600.
3 0
3 years ago
Read 2 more answers
Given: △CGF ,CG=GF=CF=and, KOPS is a square inside this triangle with one side on CF and its two vertices on CG and GF
shepuryov [24]

Answer:

  AKPOS/ACGF = 28√3 -48 ≈ 0.497423

Step-by-step explanation:

Let's assume the square is a unit square. Then the height of the triangle is ...

  1 +(√3)/2 = h

and half the base of the triangle is ...

  h/√3 = (√3)/3 +1/2 = b/2

The area of the triangle is the product of these:

  A = (1/2)bh

  = (2 +√3)/2 × (3 +2√3)/6

  = (6 +3√3 +4√3 +6)/12 = (12 +7√3)/12

So, the ratio of the area of the square to that of the triangle is the inverse of this, or ...

  (square area)/(triangle area) = 12/(12+7√3)

  (square area)/(triangle area) = 28√3 -48

8 0
3 years ago
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