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3 years ago

Find x in the right triangle. A) 63 B) 175 C) 147 D) 324

Mathematics

2 answers:

xenn [34]3 years ago

7 0

Answer: C

Step-by-step explanation:The solution is 7

. This problem can be solved using the Pythagorean Theorem leg2 + leg2 = hyp2. 142 - 72=147,

147

Wewaii [24]3 years ago

6 0

X=63 because it does

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Three friends, Jose, Michael, and Andrea, play a game in which each decides to be either a liar or a truth teller. A liar must a

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This question is based on logic.

As given, there are three friends, Jose, Michael, and Andrea. They are playing a game where each decides to be either a liar or a truth teller. A liar must always lie and a truth teller must always tell the truth.

As Michael stated, "Jose said that he is a liar." this means Michael is a truth teller because as per the game rule, he is telling the truth. So this gives Jose as a liar.

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Hence, Michael is a truth teller and Jose ans Andrea are liars.

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3 years ago

Please help, best answer will be marked brainliest

jonny [76]

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3 years ago

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mario62 [17]

Answer:

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Step-by-step explanation:

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3 years ago

(b) John begins his jogging workout by running faster and faster for about a minute. Once he hits a comfortable pace, he

Over [174]

Answer:

What am i supposed to answer?

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3 years ago

The following data represent the pulse rates? (beats per? minute) of nine students enrolled in a statistics course. Treat the ni

charle [14.2K]

Answer:

(a)77.4bpm

(b)Mean of Sample 1 = 70.3 beats per minute.

Mean pulse of sample 2 = 70 beats per minute.

(c)

The mean pulse rate of sample 1 underestimates the population mean.
The mean pulse rate of sample 2 underestimates the population mean.

Step-by-step explanation:

(a)Population mean pulse.

The pulse of the nine students which represent the population are:

Perpectual Bempah 64
Megan Brooks 77
Jeff Honeycutt 89
Clarice Jefferson 69
Crystal Kurtenbach 89
Janette Lantka 65
Kevin McCarthy 88
Tammy Ohm 69
Kathy Wojdya 87

$\text{Population Mean} =\dfrac{64+77+89+69+89+65+88+69+87}{9} \\=\dfrac{697}{9} \\\\=77.44$

The population mean pulse is approximately 77.4 beats per minute.

(b)Sample 1: {Janette,Clarice,Megan}

Janette: 65bpm
Clarice: 69bpm
Megan: 77bpm

Mean of Sample 1

$\text{Sample 1 Mean} =\dfrac{65+69+77}{3} \\=\dfrac{211}{3} \\\\=70.3$

Sample 2: {Janette,Clarice,Megan}

Perpetual: 64bpm
Clarice: 69bpm
Megan: 77bpm

Mean of Sample 2

$\text{Sample 2 Mean} =\dfrac{64+69+77}{3} \\=\dfrac{210}{3} \\\\=70$

The mean pulse of sample 1 is approximately 70.3 beats per minute.

The mean pulse of sample 2 is approximately 70 beats per minute.

(c)

The mean pulse rate of sample 1 underestimates the population mean.
The mean pulse rate of sample 2 underestimates the population mean.

7 0

3 years ago