Applying limits, it is found that since $a \neq 0, \frac{a}{2} \neq 0$ , and hence the horizontal asymptote is not y = 0, thus not being on the x-axis.

The function is given by:

$F(x) = \frac{(ax - 3)(x - 2)}{2(x + 3)(x - 2)}$

The horizontal asymptote is the limit of the function as x goes to infinity, hence:

$y = \lim_{x \rigtharrow \infty} F(x) = \lim_{x \rigtharrow \infty} \frac{(ax - 3)(x - 2)}{2(x + 3)(x - 2)}$

Considering only the terms with the highest exponents:

$y = \lim_{x \rigtharrow \infty} \frac{ax^2}{2x^2} = \frac{a}{2}$

Since $a \neq 0, \frac{a}{2} \neq 0$ , and hence the horizontal asymptote is not y = 0, thus not being on the x-axis.

For more on horizontal asymptotes and limits, you can check brainly.com/question/11598999

3 0

2 years ago

Find x in this right triangle.

maks197457 [2]

Answer:

x = 12

Solve for x:

Using Pythagorean Theorem

a^2 + b^2 = c^2

a = 9

c = 15

b = x

9^2 + x^2 = 15^2

81 + x^2 = 225

x^2 = 144 | sqrt

x = 12

4 0

3 years ago

1. Evaluate the following: PLEASE HELP ITS DUE AT 4!!!!!

Evgesh-ka [11]

1) 14
2) -10
3) 23
Tell me if you need details

7 0

3 years ago

Read 2 more answers

Is -66 rational or irrational ?

mel-nik [20]

Answer:

It's rational because it's not a decimal numbet

8 0

3 years ago

Bar ModelMath show me 8÷2=4​

Bar ModelMath show me 8÷2=4