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3 years ago

Combine like terms and classify the polynomial by the number of terms.

2 answers:

8 0

Like you said combine like terms.
You would first combine: 7x and 3x since addition comes first.
Your will get: 10x-x
Next: You would subtract x from 10x since that's all you have left to do.
Your answer would be: 7x, which is a monomial.
HOPE THIS HELPS! ^_^

rewona [7]3 years ago

6 0

Your awnser would be..... B. monomial

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Solve the following system: y = x + 3 3x + y = 19 (7,4) (-4,7) (4,7) (4,-7)

Goryan [66]

For this case we have the following system of equations:

$y = x + 3\\3x + y = 19$

We solve by the substitution method:

We substitute the first equation in the second equation:

$3x + x + 3 = 19$

We add similar terms:

$4x + 3 = 19$

We subtract 3 from both sides of the equation:

$4x = 19-3\\4x = 16$

We divide between 4 on both sides of the equation:

$x = \frac {16} {4}\\x = 4$

We look for the value of the variable y:

$y=x+3\\y=4+3\\y=7$

Finally, the solution of the system is:

$(x, y) :( 4,7)$

Answer:

$(x, y) :( 4,7)$

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3 years ago

Ninety-nine is what percent of 150?

pickupchik [31]

Answer:

Step-by-step explanation:

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3 years ago

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Write an equuation of the line that passes thorugh the given points -3,1 and 0,-8

disa [49]

Answer:y=5x-8

Step-by-step explanation:

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3 years ago

HELP, WILL MARK BRAINLIEST+100 POINTS. PLEEEEES Square EFGH is drawn on a coordinate plane. Diagonal FH is on the line y − 3 = n

vova2212 [387]

1) Slope of diagonal GE: 3

2) Equation of the line: $x-y=P-Q$

3) Slope of the line: 1

4) y-intercept: 4

Step-by-step explanation:

Here the diagonal FH is given by the line with equation

$y-3=-\frac{1}{3}(x+9)$

This line is written in the form

$y-y_0 = m(x-x_0)$

where m is the slope of the line and $(x_0,y_0)$ are the coordinates of a point on the line.

Therefore, for line FH we have:

$m=-\frac{1}{3}$ (slope)

$(x_0,y_0)=(-9,3)$

Diagonal GE is perpendicular to diagonal FH (the diagonals in a square are perpendicular): this means that its slope must be equal to the inverse reciprocal of the slope of FH. THerefore, the slope of diagonal GE is

$m_{GE}=-\frac{1}{m_{FH}}=-\frac{1}{-1/3}=3$

Two lines are said to be parallel when they have same slope.

Here, we see that the line given in the plot passes through the points

$(x_1,y_1)=(0,5)\\(x_2,y_2)=(-3,2)$

Therefore the slope of the line shown is

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{5-2}{0-(-3)}=1$

This means that also the line that we want to find must have slope of 1:

$m=1$

Now we can use the following form to write the equation of this line:

$y-y_0 = m(x-x_0)$

where:

$m=1$

$(x_0, y_0)=(P,Q)$ is the point that must be on the line

Therefore,

$y-Q=1(x-P)\\y-Q=x-P\\x-y=P-Q$

In order to solve this problem, we have to find the slope of the side WV.

The coordinates of the two points are:

$V(a+5,b-1)\\W(a+3,b-3)$

Therefore, the slope of side WV is given by:

$m=\frac{y_W-y_V}{x_W-x_V}=\frac{(b-3)-(b-1)}{(a+3)-(a+5)}=\frac{-2}{-2}=1$

And we said that two lines are parallel if they have same slope: therefore, the slope of the line parallel to the line that contains side VW is also 1.

The line given in this problem has equation:

$y=\frac{4}{3}x+1$