The equation of the tangent line will be y = -3x + 8.
<h3>What is a linear equation?</h3>
A straight line on the coordinate plane is represented by a linear equation.
A linear equation always has the same and constant slope.
The formula for a linear function is f(x) = ax + b, where a and b are real values.
Given curve
f(x) = x² - 7x + 12
The slope of the tangent equation = the first derivative of a function at that point (2,2).
So,
f'(x) = m = 2x - 7
At (2,2) ⇒ m = -3
Now let's say the equation of tangent
y = mx + c
2 = (-3)2 + c
c = 8
So,
Equation of tangent line on the curve f(x) = x² - 7x + 12 will be y = -3x + 8.
For more about the linear equation,
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(f o g)(x) is the composition of function where we substitute one function into other function.
So, (f o g)(x) = f( g(x) )
The given functions are f(x) = -8x+6 and g(x) = x³.
So,we need to plug in x³ for g(x) in f(x). Therefore,
(f o g)(x) = f( g(x) )
= f (x³) Replace g(x) with x³.
= -8x³ + 6 Replace x³ with x in f(x).
So, (f o g)(x) = -8x³ + 6.
I was actually just learning this. ^-^
To find the intersection, look at the numbers. and see what numbers do both groups have in common.
In this case, we have { 2, 4, 6, 9 } and { 3, 5, 8 }
As you can see, they both have nothing in common. Number wise.
So the answer would be Null.
Answer:
g = -1
Step-by-step explanation:
Since the slope is -5, this means that as the x value increases by 1, the y value decreases by -5.
Since the point (2, g) has a x value that is one less than the x value of the point (3, -6), we can find g by adding 5 to the second point's y value.
-6 + 5
= -1
So, the point will be (2, -1), and g = -1
Answer:
y = 3x
Step-by-step explanation:
slope of line = 3
passing through = (0, 0)
The equation of line passing through a point and the slope is given is
y - 0 = 3 (x - 0)
y = 3 x
Thus, the equation of line is given by y = 3 x.